STAT 200 Week 5 Homework Problems
7.1.2
According to the February 2008 Federal Trade Commission report on
consumer fraud and identity theft, 23% of all
... [Show More] complaints in 2007
were for identity theft. In that year, Alaska had 321 complaints of
identity theft out of 1,432 consumer complaints ("Consumer fraud
and," 2008). Does this data provide enough evidence to show that
Alaska had a lower proportion of identity theft than 23%? State the
random variable, population parameter, and hypotheses.7.1.6
The population
proportion=0.23 n=number
of complaints=1432 Alaska
had complaints=321=x So,
sample proportion=nx=1432321
=0.2242 H0: p=0.23 against H1: p<0.23
Z statistic,
Z=np^(1−p^)p^−0.23
~N(0,1) Obs(Z)=(-)0.52
H0: p=0.23 against H1: p<0.23
p value=0.30 (Excel Formula: NORM.S.DIST(0.52,1))
As,p value> α (level of significance). Hence there is not enough
evidence to support the claim that, Alaska had a lower proportion of
identity theft than 23% .
Appropriate level of significance = 0.05
7.2.4
According to the February 2008 Federal Trade Commission report on
consumer fraud and identity theft, 23% of all complaints in 2007
were for identity theft. In that year, Alaska had 321 complaints of
identity theft out of 1,432 consumer complaints ("Consumer fraud
and," 2008). Does this data provide enough evidence to show that
Alaska had a lower proportion of identity theft than 23%? Test at
the 5% level.
H0 : p = 0.23
μ=299,710.5 km/sec μ<299,710.5
lm/sec H1 : p < 0.23
Z critical value = -1.645 at 5%
level Sample proportion
'p' = 321/1432 = 0.2242
Z stat = (p - P) / sqrt(PQ/n)
This study source was downloaded by 100000871 87 81 91 23 01 41379 from CourseHero.com on 09 6-1232-2021 14:1 31 4:2 52 0 GMT -05:00= (0.2242 - 0.23) / sqrt(0.23*1-0.23/1432)= -0.52 Here - Z stat=
-0.52 >
-1.645
Fail to reject Ho, therefore, there is no sufficient evidence of identity
theft lower than 23%.
7.2.6
In 2008, there were 507 children in Arizona out of 32,601 who were
diagnosed with Autism Spectrum Disorder (ASD) ("Autism and
developmental," 2008). Nationally 1 in 88 children are diagnosed
with ASD ("CDC features -," 2013). Is there sufficient data to show
that the incident of ASD is more in Arizona than nationally? Test at
the 1% level. [Show Less]