Chem 152 Experiment #5: Thermodynamics II
The Temperature Dependence of the Solubility Product (Ksp)
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report must be typed
Type the calculation you used to determine [K+] in the measured and original solutions above.
Intensity= (984000 M-1
)[K+
] + 7.8
290 = (984000 M-1
)[K+
] + 7.8 ଶ.଼ாିସ ெ
௫
=
ଵ
ଶହ
[K+
] = 290 -7.8 x = (2.87E-04 M)(2500)
984000 M-1
x = 0.718 M
Place your calibration plot (intensity vs. concentration of K+) here. Make your plot big enough to cover this
instruction box so that it is large enought for someone else to read.
Add a Trendline and Trendline Eqn and on your plot and be sure to include titles for the plot and each axis.
y = 984000x + 7.8
R² = 0.9998
70
120
170
220
270
320
370
6.50E-05 1.15E-04 1.65E-04 2.15E-04 2.65E-04 3.15E-04 3.65E-04
Intensity
Concentration of K+
(M)
Calibration Plot of Intensity vs. Concentration of K+ (M)
Page 1 of 4
3 pts
B. Titrations of KHP Samples With and Without KCl
1.00 mL
Table 5: Titration Data and Calculations for Solutions #1-6
Solution # Temperature
(
oC)
Temperature
(K)
Initial buret
reading (mL)
Final buret
reading (mL)
mL NaOH
added mmoles HP- [HP-
] (M) Ksp
1/T
(K-1)
ln Ksp
1 4.0 277.2 0.00 2.60 2.60 0.263 0.263 0.0692 0.00361 -2.671
2 22.6 295.8 0.00 3.25 3.25 0.328 0.328 0.108 0.00338 -2.226
3 35.4 308.6 0.00 5.20 5.20 0.525 0.525 0.276 0.00324 -1.287
4 41.6 314.8 0.00 7.10 7.10 0.717 0.717 0.514 0.00318 -0.666
5 47.6 320.8 0.00 7.35 7.35 0.742 0.742 0.551 0.00312 -0.596
6 59.4 332.6 0.00 10.00 10.00 1.010 1.010 1.020 0.00301 0.020
2 pts
2 pts
2 pts
4 pts
slope -4734 K R 8.314 J/mol*K
y-intercept 14.171 H
o
Soln 39.4 kJ/mol
S
o
Soln 117.8 J/mol*K
2 pts
2 pts
mL of KHP(aq) used in titrations of Solutions #1-6
Place your plot of ln(Ksp) vs 1/T(K) here. Make your plot big enough to cover this instruction box so that it is large
enought for someone else to read.
Add a Trendline and Trendline Eqn and on your plot and be sure to include a titles for the plot and each axis.
Type the calculation for determining [NaOH] for Run #1.
moles/liters=M [NaOH]
(0.000641moles/0.00635liters)= 0.101M [NaOH]
Calculate the % difference between Runs #1 and #2.
(6.40-6.35)/((6.4 [Show Less]