CHEM 103
MODULE 5 EXAM 2022
Question 1
Click thislink to accessthe Periodic Table. This may be helpfulthroughout the exam.
Show the determination of
... [Show More] the charge on the ion formed by the Se34 atom. Se34
(nonmetal = gain electrons) 1s
2 2s
2 2p
6 3s
2 3p
6 4s
2 3d
10 4p
4 gain 2e
→ Se
-2
Question 2
Click thislink to accessthe Periodic Table. This may be helpfulthroughout the exam.
H = 2.1
Li = 1.0 Be = 1.5 B = 2.0 C = 2.5 N =
3.0 O= 3.5 F = 4.0
3
3
Na = 1.0
2.1
Mg = 1.2
S = 2.5
Al = 1.5
Cl = 3.0
Si = 1.8 P =
K = 0.8
2.0
Ca = 1.0
Se = 2.4
Ga = 1.6
Br = 2.8
Ge = 1.8 As =
Using the electronegativities from the table above, show the determination
of the polarity of each different type of bond in the following molecule
H-C bond electronegativity difference = 2.5 - 2.1 = 0.4 <0.5
bond is Nonpolar
C-O bond electronegativity difference = 3.5 - 2.5 = 1.0 1.6 - 0.5
bond is Polar
Question 3
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On a piece of scratch paper, draw the Lewis structure for the ClO -1
ion. Then
choose the correct Lewis structure for ClO -1
from the options listed below.
(B)
Question 4
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On a piece of scratch paper, draw the Lewis structure for H2SO3. Then choose
the correct Lewis structure for H2SO3 from the options listed below.
(D)
Question 5
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Determine the electron geometry and explain your answer for the Si atom in
SiH4.
The Si atom in SiH4 has 4 groups of electrons around it in its Lewis structure,
therefore, its electron geometry would be tetrahedral.
Question 6
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Determine the hybridization and explain your answer for the Si atom in SiH4.
The Si atom in SiH4 has 4 groups of electrons around it in its Lewis structure,
therefore, its hybridization would be sp
3
.
Question 7
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Determine the shape and explain your answer for HCN.
The C atom in HCN has 2 groups of electrons around it in its Lewis structure,
therefore, its electron geometry would be linear and since there are 2 atoms
around the central C atom, the shape would be linear.
Question 8
Click thislink to accessthe Periodic Table. This may be helpfulthroughout the exam.
H = 2.1
Li = 1.0
3.0
Be = 1.5 B = 2.0
O= 3.5 F = 4.0
C = 2.5 N =
Na = 1.0
2.1
Mg = 1.2 Al = 1.5
S = 2.5 Cl = 3.0
Si = 1.8 P =
K = 0.8
2.0
Ca = 1.0 Ga = 1.6
Se = 2.4 Br = 2.8
Ge = 1.8 As =
Use the electronegativities above and your knowledge of the shape of PH3 to
determine the molecular polarity of PH3 explaining your answer in detail.
The shape of PH3 is triangular pyramid and since the P-H bonds are all
nonpolar, PH3 would be nonpolar since all the bonds are nonpolar.
Question 9
Click thislink to accessthe Periodic Table. This may be helpfulthroughout the exam [Show Less]