Chem 103 Module 1 to 6 Exam Questions & Answers / Portage learning (2021)
Chem 103 Module 1 to 6 Exam answers Portage learning.
MODULE 1 EXAM
Question
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1. Convert 845.3 to exponential form and explain your answer.
2. Convert 3.21 x 10-5 to ordinary form and explain your answer.
1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x 102
2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 places = 0.0000321
Question 2
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Using the following information, do the conversions shown below, showing all work:
1 ft = 12 inches
1 mile = 5280 feet
kilo (= 1000) 1/100)
1 pound = 16 oz
1 ton = 2000 pounds
milli (= 1/1000) deci (= 1/10)
1 gallon = 4 quarts 1 quart = 2 pints
centi (=
1. 24.6 grams = ? kg
2. 6.3 ft = ? inches
1. 24.6gramsx1kg/1000g=0.0246kg 2. 6.3 ft x 12 in / 1 ft = 75.6 inches
please always use the correct units in your final answer
Question 3
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Do the conversions shown below, showing all work: 1. 28oC=?oK
2. 158oF = ? oC
3. 343oK = ? oF
1. 28oC + 273 = 301 oK +273
2. 158oF - 32 ÷ 1.8 = 70 oC -32 ÷1.8
3. 343oK-273=70oCx1.8+32=158oF
Question 4
oC → oK (make larger)
oF → oC (make smaller) oK→oC→oF
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Be sure to show the correct number of significant figures in each calculation.
1. Show the calculation of the mass of a 18.6 ml sample of freon with density of 1.49 g/ml
2. Show the calculation of the density of crude oil if 26.3 g occupies 30.5 ml.
1. M=DxV=1.49x18.6=27.7g
2. D=M/V=26.3/30.5=0.862g/ml
Question 5
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1. 3.0600 contains ? significant figures.
2. 0.0151 contains ? significant figures.
3. 3.0600 ÷ 0.0151 = ? (give answer to correct number of significant figures)
1. 3.0600 contains 5 significant figures.
2. 0.0151 contains 3 significant figures.
3. 3.0600 ÷ 0.0151 = 202.649 = 203 (to 3 significant figures for 0.0151)
Question 6
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Classify each of the following as an element, compound, solution or heterogeneous mixture and explain your answer.
1. Coca cola
2. Calcium
3. Chili
1. Coca cola - is not on periodic table (not element) - no element names (not compound)
appears to be one substance = Solution
2. Calcium - is on periodic table = Element
3. Chili - is not on periodic table (not element) - no element names (not
compound)
sauce) = Hetero Mix
Question 7
appears as more than one substance (meat, beans,
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Classify each of the following as a chemical change or a physical change
1. Charcoal burns
2. Mixing cake batter with water
3. Baking the batter to a cake
1. Charcoal burns - burning always = chemical change
2. Mixing cake batter with water - mixing = physical change
3. Baking the batter to a cake - baking converts batter to new material =
chemical change
Question 8
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Show the full Nuclear symbol including any + or - charge (n), the atomic number (y), the mass number (x) and the correct element symbol (Z) for each element for which the protons, neutrons and electrons are shown - symbol should appear as follows: xZy+/- n
31 protons, 39 neutrons, 28 electrons
31 protons = Ga31, 39 neutrons = 70Ga31, 28 electrons = (+31 - 28 = +3)
Question 9
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Name each of the following chemical compounds. Be sure to name all acids as acids (NOT for instance as binary compounds)
1. PF5
2. Al2(CO3)3 3. H2CrO4
1. PF5 - binary molecular = phosphorus pentafluoride
2. Al2(CO3)3 - nonbinary ionic = aluminum carbonate
= 70Ga +3 31
3. H2CrO4 - nonbinary acid = chromic acid
incorrect fluoride prefix
Question 10
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Write the formula for each of the following chemical compounds explaining the answer with appropriate charges and/or prefixes and/or suffixes.
1. Carbon monoxide
2. Manganese (IV) acetate
3. Phosphorous acid
1. Carbon monoxide - ide = binary, mono = 1 O = CO
2. Manganese (IV) acetate - Mn+4, C2H3O -1 = Mn(C2H3O2)4 2
3. Phosphorous acid - nonbinary acid of H + phosphite (PO -3) = H PO
MODULE 2 EXAM
Question 1
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Show the calculation of the molecular weight for the following compounds, reporting your answer to 2 places after the decimal.
1. Al2(CO3)3
2. C8H6NO4Cl
1. 2Al+3C+9O=233.99
3
3
3
2. 8C+6H+N+4O+Cl=215.59
Question 2
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Show the calculation of the number of moles in the given amount of the following substances. Report your answerto 3 significant figures.
1. 13.0 grams of (NH4)2CO3
2. 16.0 grams of C8H6NO4Br
1. Moles = grams / molecular weight = 13.0 / 96.09 = 0.135 mole
2. Moles = grams / molecular weight = 16.0 / 260.04 = 0.0615 mole
Question 3
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Show the calculation of the number of grams in the given amount of the following substances. Report your answer to 1 place after the decimal.
1. 1.20 moles of (NH4)2CO3
2. 1.04 moles of C8H6NO4Br
1. Grams = Moles x molecular weight = 1.20 x 96.09 = 115.3 grams
2. Grams = Moles x molecular weight = 1.04 x 260.04 = 270.4 grams
Question 4
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Show the calculation of the percent of each element present in the following compounds. Report your answer to 2 places after the decimal.
1. 2.
(NH4)2CrO4 C8H8NOI
%N = 2 x 14.01/152.08 x 100 = 18.43%
%H = 8 x 1.008/152.08 %O = 4 x
%H = 8 x 1.008/261.05 %O = 1 x
1.
x 100 = 5.30%
%Cr = 1 x 52.00/152.08 x 100 = 34.20% 16.00/152.08 x 100 = 42.08%
2. %C = 8 x 12.01/261.05 x 100 = 36.80% x 100 = 3.09%
%N = 1 x 14.01/261.05 x 100 = 5.37% 16.00/261.05 x 100 = 6.13%
%I = 1 x 126.9/261.05 x 100 = 48.61%
Question 5
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Show the calculation of the empirical formula for each compound whose elemental composition is shown below.
38.76% Ca, 19.87% P, 41.27% O
38.76% Ca / 40.08 = 0.9671 / 0.6416 = 1.5 x 2 = 3
19.87% P / 30.97 = 0.6416 / 0.6416 = 1 x 2 = 2 41.27%O/16.00=2.579/0.6416=4x2=8 → Ca3P2O8
Question 6
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Balance each of the following equations by placing coefficients in front of each substance.
1. C6H6 +O2 →CO2 +H2O
2. As + O2 → As2O5
3. Al2(SO4)3 + Ca(OH)2 → Al(OH)3 + CaSO4
1. 2C6H6 + 15O2 → 12CO2 + 6H2O
2. 4As + 5O2 → 2As2O5
3. Al2(SO4)3 + 3 Ca(OH)2 → 2 Al(OH)3 + 3 CaSO4 [Show Less]