BIOLOGY 130 CHAPTER 12 STUDY QUESTIONS
Question 1 of 10 1.0/ 1.0 Points
Determine what statements describe Huntington’s disease? Select all that
... [Show More] apply.
A. The disease is caused by a delayed action gene
B. The diseases is autosomal dominant
C. The disease is sexlinked so it is mostly seen in men
D. Offspring have a 50% chance of inheriting the gene
E. t is recessive lethal
Question 2 of 10 1.0/ 1.0 Points
What statement describes Xlinked traits? Select all that apply.
A. Women can be carriers because they can be heterozygous for the trait
B. Xlinked traits are more common in men
C. Males are never carriers since they only receive one X chromosome
D. Males inherit Xlinked traits from their fathers
E. Women only have to have one affected gene to show the trait
Question 3 of 10 1.0/ 1.0 Points
If genes are completely linked, all the offspring will be . A.dominant
B.hybrids C.parental D.recessive E.recombinants
Question 4 of 10 1.0/ 1.0 Points
A and Z are independent events. The probability that A occurs is ¼. The probability that Z occurs is ¼. What is the probability that both will occur?
A.1/4 B.1/8 C.1/3 D.1/2
E.1/16
Question 5 of 10 1.0/ 1.0 Points
In a monohybrid cross from heterozygous parents, of the offspring would be what genotypes?
Select all that apply.
A. Homozygous recessive
B. Homozygous dominant
C. Heterozygotes
D. Homozygous recessives
E. Homozygous dominants
F. Heterozygote
Question 6 of 10 1.0/ 1.0 Points
Sickle cell anemia is a recessive trait. A cross between two heterozygotes would produce what phenotypic ratio?
A.1:2:1 B.3:1
C.2:2
D.1:3
E.4:0
Question 7 of 10 1.0/ 1.0 Points
Low pitched male voices (RR) and a high pitched male voice (rr). Heterozygotes have a baritone voice. This is an example of .
A.incomplete dominance B.codominance
C.Mendelian genetics (dominance and recessive D.multiple alleles
Question 8 of 10 1.0/ 1.0 Points
If a cross for widow’s peak was conducted between a homozygous dominant and a heterozygote, it is expected that all organisms of the offspring will have widow’s peak. Even though all have the widow’s peak, they can .
A. be phenotypically different
B. have more than one allele from a parent for the trait C.be genotypically different
D.have the exact same alleles
Question 9 of 10 1.0/ 1.0 Points
The allele for widows peak (H) is dominant for the allele for no widows peak (h). At a different gene locus, the allele for hitchhikers thumb (D) is dominant to the allele for nonhitchhikers thumb (d). A man is heterozygote for the traits and marries a woman who has no widows peak and is heterozygote for hitchhikers thumb. What is the man’s genotype?
A.HHDD
B.HhDd [Show Less]