1.
THE NEXT TWO QUESTIONS ARE BASED ON THE FOLLOWING INFORMATION:
Pernell's scores on her last five chemistry exams were 81, 92, 87, 89, and
... [Show More] 94.
What is the approximate average of her scores? A. 81
B. 84
C. 89
D. 91 - C. To find the average of Pernell's scores, add them up and then divide by the number of scores (5 in this case). In other words,
81 + 92 + 87 + 89 + 94 = 443
443/5 = 89
2.
THE NEXT QUESTIONS ARE BASED ON THE FOLLOWING INFORMATION:
Pernell's scores on her last five chemistry exams were 81, 92, 87, 89, and 94.
What is the medium of Pernell's scores? A. 87
B. 89
C. 92
D. 94 - B. To find the median, list the series of numbers form least to greatest. The middle number represents the median -- in this case 81, 87, 89, 92, 94.
The number 89 is in the middle, so it is the median.
Gordon purchased a television when his local electronics store had a sale. The television was offered at 30% off its original price of $472. What was the sale price that Gordon paid?
A. $141.60 B. $225.70 C. $305.30
D. $330.40 - D. The television is 30% off its original price of $472. 30% of 472 is 141.60. (0.30)(472) = 141.60
472 - 141.60 = 330.40
Thus, Gordon paid $330.40 for the television.
Simplify the following expression: (2/3) / (4/15) X (5/8)
A. 1 9/16 B. 1 1/4 C. 2 1/8
D. 2 - A. To simplify, proceed it he order of the operations: (2/3) / (4/15) = (3/2) x (15/4) = 30/12 = 10/2 = 5/2
5/2* 5/8 = 25/16 = 1 9/16
Simplify following expression:
0.0178 X 2.401
A. 2.0358414
B. 0.0427378
C. 0.2341695
D. 0.3483240 - B. This is a simple matter of multiplication. The production is 0.00427378.
Tom needs to buy ink cartridges and printer paper. Each ink cartridge costs $30. Each ream of paper cost $5. He has $100 to spend. Which of the following inequalities may be used to find the combinations of ink cartridges and printer paper that he may purchase?
A. 30c + 5p < 100
B. 30c + 5 p < 100
C. 30c + 5p > 100
D. 30c + 5p > 100 - A. The inequality will be less than or equal to, since he may spend $100 or less on his purchase.
Solve for x:
4(2x-6) = 10x-6
A. x= 5 B. x= - 7
C. x= - 9
D. x= 10 - C. Multiplying the equation results in the following:
8x - 24 = 10x - 6
+6 +6
8x - 18 = 10x
-8x -8x
-18 = 2x
-18/2 = 2x/2
-9 = x
x = -9
Erma has her eye on two sweaters at her favorite clothing store, but she has been waiting for the store to offer a sale. This week, the store advertises that all clothing purchases, including sweaters, come with an incentive: 25% off a second item of equal or lesser value. One sweater is $50 and the other is $44. If Erma purchases the sweaters during the sale, what will she spend?
A. $79 B. $81 C. $83
D. $85 - C. Erma's sale discount will be applied to the less expensive sweater, so she will receive the $44 sweater for 25% off.
This amount to a discount of $11, so the cost of the sweater will be $33.
44 x .25 = 11
44-11 = $33
Added to the cost of the $50 sweater, which is not discounted, Erma's total is $83.
$33 + $55 = $83.
Simplify the following expression:
1.034 + 0.275 - 1.294
A. 0.015
B. 0.15
C. 1.5
D. -0.15 - A. Start by adding the first two expressions, and then subtract 1.294 from the sum:
1.034 + 0.275 - 1.294
1.034 + 0.275 = 1.309
1.309 - 1.294 = 0.015
The graph below shows the weekly church attendance among residents in the town of Ellsford, with the town having five different denominations: Episcopal, Methodist, baptist, Catholic, and Orthodox. Approximately what percentage of church-goers in Ellsford attends Catholic Churches?
A. 23%
B. 28%
C. 36%
D. 42% - B. Adding up the number of church-goers in Ellsford resulting about 1450 residents who attend a church in the town each week. There are approximately 400 people in Ellsford who attend a Catholic Church each week. This number represents about 28% of the 1450 church-goers in the town.
Jerry needs to load four pieces of equipment on to a factory elevator that has a weight limit of 800 pounds. Jerry weighs 200 pounds. What would the average weight of each item have to be so that the elevator's weight limit is not exceeded assuming Jerry accompanies the equipment?
A. 128 pounds
B. 150 pounds
C. 175 pounds
D. 180 pounds - B. To solve, first subtract Jerry's weight from the total permitted: 800-200 = 600
Divide 600 by 4 (the four pieces of equipment) to get 150, the average weight. 600/4 = 150
Simplify the following expression: 4 (2/3) / 1 (1/6)
A. 2
B. 3 1/3 C. 4
D. 4 1/2 - C. Turn both expressions into fractions, and then multiply the first by the reverse of the second:
= (14/3) / (7/6)
= (14/3) X (6/7)
= 14 x 6 = 84
= 3 x 7 = 21
84/21 = 4
Solve for x: 2x + 4 = x - 6
A. x = - 12 B. x = 10 C. x = - 16
D. x = - 10 - D. Begin by subtracting 4 from both sides, then subtract x form both sides:
2x + 4 = x - 6
-4 - 4
2x = x - 10
- x. - x
x = - 10
Solve for x: 2x - 7 = 3
A. x = 4 B. x = 3
C. x = -2
D. x = 5 - D. To solve the equation for x, you can follow the steps below:
2x - 7 = 3
+7 +7
2x = 10
2x/2 = 10/2
x = 5
What kind of association does the scatter plot show? A. linear, positive
B. linear, negative C. quadratic
D. no association - D. The points do not show any trend line or trend curve at all. So, there is no association int he scatter plot.
If Stella's current weight is 56 kilograms, which of the following is her approximate weight in pounds? (Note: 1 kilogram is approximately equal to 2.2 pounds.)
A. 123 pounds
B. 110 pounds
C. 156 pounds
D. 137 pounds - A. To find the correct answer, simply multiply 56 by 2.2.
56 x 2.2 = 123.2
Approximately 123.
This is Stella's weight in pounds.
Which of the following is listed I order from least to greatest? A. -3/4, - 7 3/4, -8, 18%, 0.25, 2.5
B. - 8, - 7 4/5, - 3/4, 0.25, 2.5, 18%
C. 18%, 0.25, - 3/4, 2.5, - 7 4/5, - 8
D. -8, - 7 4/5, - 3/4, 18%, 0.25, 2.5 - D. The smallest negative integers are those that have the largest absolute value.
- The negative integers, writing in order from least to greatest, are - 8, - 7 4/5, - 3/4.
- The percentage, 18% can be written as the decimal, 0.18; 0.18 is less than 0.25.
- The decimal, 2.5, is the greatest rational number given.
- The values, -8, -7 4/5, -3/4, 18%, 0.25, 2.5.
Between the years 2000 and 2010, the number of births in the town of Daneville increased form 1432 and 2219. Which of the following is the approximate percent of increase int he number of births during those ten years?
A. 55%
B. 36%
C. 64%
D. 42% - A.
- Begin by subtracting 1432 from, 2219. 2219-1432 = 787
- Then, divide 787 by 1432 to find the percent of increase: 0.549. 787/1432 = 0.549
Round up: approximately 55% increase in births between 2000 and 2010.
Simplify the following expression: (1/4) x (3/5) / 1 (1/8) A. 8/15
B. 27/160 C. 2/15
D. 27/40 - C. Solve the equation in the order of operations: 1/4 x 3/5 = 3/20
Follow this up with division, which requires a reversal of the fraction: (3/20) / (9/8) (1 1/8 = 1*8 =8+1 = 9 = 9/8)
3/20 x 8/9 = 24/180
- The result simplifies to 2/15
While at the local ice skating rink, Cora went around the rink 27 times total. She slipped and fell 20 of the 27 times she skated around the rink. What approximate percentage of the times around the rink did Cora not slip and fall?
A. 37%
B. 74%
C. 26%
D. 15% - C. Cora did not fall 7 out of 27 times.
- To find the solution, simply divide 7 by 27 to arrive to arrive at 0.259, or 25.9%. 7/27 = 0.259 = 25.9%
- Rounded up, this is approximately 26%
A can has a radius of 1.5 inches and a height of 3 inches. Which of the following best represents the volume of the can?
A. 17.2 in3
B. 19.4 in3
C. 21.2 in3
D. 23.4 in3 - C. The volume of a cylinder may be calculated using the formula V = ñr2h, where r represents the radius and h represents the height. Substituting 1.5 for r and 3 for h gives V = ñ(1/5)2(3), which simplifies to V = 21.2
- ñ represents pie
- (1/5)2 represents 1/5 squared (2).
Simplify the following expression: 3 (1/6) - 1 (5/6) A. 2 (1/3)
B. 1 (1/3)
C. 2 (1/9)
D. 5/6 - B. Since the denominator is the same for both fractions, this is simple subtraction. Start by turning each expression into a fraction: 19/6 - 11/6.
The results is
8/6 = 1 (2/6) = 1 (1/3)
Four more than a number, x, is 2 less than 1/3 of another number, y. Which of the following algebraic equations correctly represents this sentence?
A. x + 4 = 1/3y - 2 B. 4x = 2 - 1/3y C. 4 - x = 2 + 1/3y
D. x + 4 = 2 - 1/3y - A. The expression "Four more than a number, x" can be interpreted as x+4.
- This is equal to "2 less than 1/3 of another number, y," or 1/3y - 2.
- Thus, the equation is x + 4 = 1/3y - 2
Margery is panning a vacation, and she has added up the cost. Her round-trip airfare will cost $572. Her hotel cost is $89 per night, and she will be staying at the hotel for five nights. She has allotted a total of $150 for sightseeing during her trip, and she expects to spend about $250 on meals. As she books the hotel, she is told that she will receive a discount of 10% per night off the price of $89 after the first night she stays there. Taking this discount into consideration, what is the amount that Margery expects to spend on her vacation?
A. $1328.35 B. $1373.50 C. $1381.40
D. $1417.60 - C. Start by adding up the costs of the trip, excluding the hotel cost: $572 +
$150 + $250 = $972.
- Then, calculate what Margery will spend on the hotel.
- the first of her five nights at the hotel will cost her $89.
-For each of the other four nights, she will get a discount of 10% per night, or $8.90.
- This discount of $8.90 multiplied by the four nights is $35.60.
- The total she would have spent on the five nights without the discount is $445.
- With the discount, the amount goes down to $409.40.
- Add this amount to the $972 for a grand total of $1381.40.
Given the double bar graph shown below which of the following statements is true? A. Group A is negatively skewed, while group B is approximately normal.
B. Group A is positively skewed, while Group B is approximately normal.
C. Group A is approximately normal, while Group B is negatively approximately skewed.
D. Group A is approximately normal, while Group B is postively approximately skewed. - B. Data is said to be positively skewed when there are a higher number of lower values, indicating data that is skewed right.
- An approximately normal distribution shows an increase in frequency, followed by a decrease in frequency, of approximately the same rate.
A grift box has a length of 14 inches, a height of 8 inches, and a width of 6 inches. How many square inches of wrapping paper are needed to wrap the box?
A. 56
B. 244
C. 488
D. 672 - C. The surface area of a rectangular prism may be calculated using the formula SA = 2lw + 2wh + 2hl
Substituting the dimensions of 14 inches, 6 inches, and 8 inches gives: SA = 2(14)(6) + 2(6)(8) + 2(8)(14)
Thus, the surface area is 488 square inches. [Show Less]