1 + tan2θ = sec2θ cot2θ + 1 = cosec2θ = cosec2θ Sin2θ 2sinθcosθ
Equation of a straight line y - y₁ = m(x - x₁) Distance between two points d = √(x₂ - x�
1 + tan2θ = sec2θ cot2θ + 1 = cosec2θ = cosec2θ Sin2θ 2sinθcosθ Cos2θ cos²θ-sin²�
Equation of a straight line y - y₁ = m(x - x₁) Distance between two points d = √(x₂ - x�
Physics Wallah 12 Class Lakshya JEE class notes Lecture 1 Determinants..
area of sector (where θ is in radians) ½r²θ angles in 3D vectors cosθₓ =x/|a| cosθᵧ =y
1) f(x,y) =x2+6y z=2 82-3 x+6y =0 max possible error ofz: 64 = - x2 y = - 1 0z =22.0x +2oz.dy w
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