MATH 110 Module 2 Exam Questions and Answers- Portage Learning
Module 2 Exam
Exam Page 1
During an hour at a fast food restaurant, the following types
... [Show More] of sandwiches are ordered:
Cheeseburger Fish Cheeseburger Hamburger Fish Chicken
Hamburger Cheeseburger Fish Hamburger Turkey Fish Chicken
Chicken Fish Turkey Fish Hamburger Fish
Cheeseburger Fish Cheeseburger Hamburger Fish Fish
Cheeseburger Hamburger Fish Turkey Turkey Chicken Fish
Chicken Cheeseburger Fish Turkey Fish Fish Hamburger
Fish Fish Turkey Chicken Hamburger Fish Cheeseburger
Chicken Chicken Turkey Fish Hamburger Chicken Fish
a) Make a frequency distribution for this data.
Sandwiches Frequency
b) Make a relative frequency distribution for this data. Include relative percentages on this table.
Copied and pasted from answer above to save on time not having to re-type
Sandwiches Calculation Relative Frequency Relative Percentage
Answer Key
During an hour at a fast food restaurant, the following types of sandwiches are ordered:
Cheeseburger Fish Cheeseburger Hamburger Fish Chicken
Hamburger Cheeseburger Fish Hamburger Turkey Fish Chicken
Chicken Fish Turkey Fish Hamburger Fish
Cheeseburger Fish Cheeseburger Hamburger Fish Fish
Cheeseburger Hamburger Fish Turkey Turkey Chicken Fish
Chicken Cheeseburger Fish Turkey Fish Fish Hamburger
Fish Fish Turkey Chicken Hamburger Fish Cheeseburger
Chicken Chicken Turkey Fish Hamburger Chicken Fish
a) Make a frequency distribution for this data.
Major Frequency
b) Make a relative frequency distribution for this data. Include relative percentages on this table.
Consider the following data:
437 389 414 401 466 421 399 387 450 407 392 410
440 417 488
Consider the following data:
437 389 414 401 466 421 399 387 450 407 392 410
440 417 488
Find the 60th percentile of this data.
There are a total of fifteen numbers, so n= 15. In order to find the percentiles, we must put the
numbers in ascending order:
387 389 392 399 401 407 410 414 417 421 437 440 450 466 488
For the 60th percentile:
Stati sti cs - Portage Online Summer 2018
Therefore, the 60th percentile index for this data set is the 9th observation. In the list above, the 9th
observation is 417.
Exam Page 3
Consider the following data:
{22, 18, 16, 26, 20, 24}
a) Find the sample mean of this data.
22+18+16+26+20+24 = 126
n = 6
xbar = ∑xi / n
∑xi = 126
n = 6
126/6 = 21
sample mean = 21
b) Find the range of this data.
range = highest value - lowest value
high value = 26
low value = 16
26-16 = 10
Range = 10
c) Find the sample standard deviation of this data.
s^2 = variance
s = standard deviation
s^2 = ∑(xi-xbar)^2 / (n-1)
Stati sti cs - Portage Online Summer 2018
xi = 16, 18, 20, 22, 24, 26
xbar = 21
n = 6
∑(xi-xbar)^2 / (n-1) =
(16-21)^2 = 25
(18-21)^2 = 9
(20-21)^2 = 1
(22-21)^2 = 1
(24-21)^2 = 9
(26 -21)^2 = 25
70
n-1 =
6-1 =5
70/5 = 14
s^2 (variance) = 14
standard deviation (s) = √variance
√14 = 3.74
standard deviation of sample = 3.74
d) Find the coefficient of variation. [Show Less]