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CHEM219/ CHEM 219 Full Exam Pack | Modules 1, 2, 3, 4, 5, 6, 7, 8 and Final Exam | Principles of Organic Chemistry with Lab | Portage Learning | Updated 2026–2027 | Verified Q&A
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CHEM219/ CHEM 219 Module 7 – Principles of Organic Chemistry with Lab | Portage Learning | Updated
CHEM219/ CHEM 219 Module 7 – Principles of Organic Chemistry with Lab | Portage Learning | Updated 2026–2027 | Complete Questions & Verified Answers ... Show More | Grade A 2026 / 2027 Academic Year Q: Heterocycles (heterocyclic compounds) Answer cyclic organic molecules in which one or more carbon atoms are replaced by heteroatoms (elements other than carbon or hydrogen) Q: What are the most common heteroatoms? Answer oxygen, nitrogen, and sulfur Q: How many heteroatoms can be present on a heterocyclic compound? Answer More than one heteroatom can be present, and the heteroatoms can be the same or different Q: True or False: Heterocyclic compounds may contain multiple bonds and the rings may have chains or branched chains of carbons attached to them. The rings may be of a variety of sizes. Answer True Q: True or False: Heterocycles form the largest class of organic compounds known. Answer True Q: True or False: Many natural products and important drug molecules contain heterocyclic rings. Answer True Q: What are the two main subgroups of heterocyclic compounds? Answer Aromatic and aliphatic (non-aromatic) Example of non-aromatic heterocycles include molecules like cyclic ethers (epoxides) and sugars like glucose (a cyclic hemiacetal) Non-aromatic heterocycles behave very similarly to their acyclic counterparts. Q: Pyridine Answer A six-membered heterocyclic analog of benzene. In pyridine, one CH unit of the (benzene) ring is replaced by a N atom. Q: What are the bond angles between the atoms of pyridine? Answer Approximately 120 degrees Q: True or False: Like benzene, pyridine is a flat molecule with near-perfect hexagonal geometry? Answer True Q: What hybridization are the atoms of the pyridine ring? Answer sp2 Q: What makes the pyridine ring aromatic just like benzene? Answer each atom is sp2 hybridized and each contributes a single electron to the conjugated p system for a total of six p electrons, making the ring aromatic just like benzene Q: True or False: The nitrogen atom of pyridine contains a lone pair of electrons in an sp2 hybrid orbital that is NOT orientated in the same plane of the atoms in the ring (like the hydrogens that project from each carbon atom). Answer False - they are orientated in the same plane of the atoms in the ring. Q: What are the C-C bond lengths in a pyridine molecule? Answer 139 pm are intermediate between normal C-to-C sigma and pi bonds. Q: True or False: Pyridine exists as a hybrid of equivalent resonance structures as evidenced by the C-C bond length? Answer True Q: What does the circle inscribed inside of the pyridine ring represent? Answer The delocalization of the pi electrons within the six-membered ring. Q: What kind of reaction does pyridine tend to undergo and why? Answer Substitution reactions because addition reactions would destroy the aromaticity. Q: True or False: Pyridine is completely miscible in water? Answer True; unlike benzene This is due to the substitution of the N atom in the ring which changes many of the properties of the molecules. Pyridine is also miscible in most organic solvents. Q: What are the several factors that explain the ability of pyridine to dissolve in water? Answer 1. The ability of pyridine to accept hydrogen bonding interactions from water molecules due to the lone pair of electrons on the N atom. 2. The electronegative N creates a relatively strong dipole moment in the pyridine molecule, making it a polar compound overall. There is a shift of electrons away from the Cs and towards the N, making the ring Cs partially positive and the N partially negative. Q: What causes the difference in B.P. between pyridine and benzene? Answer B.P. of pyridine is 35 degrees higher than that of benzene, even though the molecular weight is negligible between the two compounds. Dipole-Dipole attractive forces between the pyridine molecules raises the B.P. as compared to benzene. Q: Pyridinium salts Answer Pyridine is a weak base and will react with strong acids to form pyridinium salts. The ability of pyridine to act as a base, coupled with its wide-ranging solubility, makes it suited to act as a proton scavenger in acid-producing reactions, like the conversion of alcohols to alkyl chlorides using thionyl chloride. Q: EAS (Electrophilic aromatic substitution) reactions Answer Reactions in which a hydrogen is replaced by an electrophile (species that seeks electrons/negative charge). Q: Under what conditions will pyridine undergo EAS reactions? Answer Slowly and very harsh conditions i.e. pyridine can be nitrated or brominated, as shown, but the reactions require very high temperatures and very strong acid catalysis. Electron withdrawal by the N makes the ring partially positive and, thus, not as receptive to attack by electrophiles like NO2+ or Br+. In addition, the strongly acidic conditions required for the formation of these electrophiles causes protonation of the N atom and the positive pyridinium ion formed as a result is even less attractive to attack by electrophiles. Q: When EAS does occur, what is the preferred position for the substitution on the ring? Answer C3 position This position is preferred as the positive charge that forms on the C during the reaction is the one position that does not put the positive charge on the electronegative N via resonance. Q: True or False: Pyridine can more easily undergo nucleophilic aromatic substitution (NAS) than EAS? Answer True In NAS, a nucleophile displaces a hydride (H-) ion or halide ion (on a substituted pyridine) from the aromatic ring. Due to the presence of the N heteroatom, the ring is partially positive and therefore is more attractive to nucleophiles, rather than electrophiles. i.e. Strong nucleophiles like alkoxide ions (RO-) and amide ions (NH2-) help to facilitate the reaction. Azines Answer heterocyclic six-membered rings with two or more N atoms present as part of the ring system Diazines Answer contain two N atoms and can exist in three different constitutional isomeric forms; pyrimidines are the most important because derivatives of pyrimidines are important bases in the nucleic acids DNA and RNA namely cytosine, thymine, and uracil. True or False: Tri- and tetrazines are also known, but no others with higher degrees of N substitution (5 or 6 N atoms) are known. Answer True What are the most important heterocyclic molecules with five-membered rings? Answer Furan (oxygen-based) Pyrrole (nitrogen-based) Thiophene (sulfur-based) differences: the heteroatom of a five-membered ring contributes two electrons (one lone pair) to the These molecules each contain a carbon ring with a single heteroatom substitution. What are some similarities and differences between five-membered rings and benzene (six membered ring)? Answer Similarities: aromatic undergo EAS rather than other modes, like addition planar (flat) aromatic pi system of the ring to make the molecule aromatic while the six-membered heterocycles have a heteroatom that contributes one electron to the aromatic pi system What are some important consequences in terms of chemistry of the molecule for the use of the lone pair of pyrrole in the aromatic pi system? Pyrrole (five-membered) is a much weaker base than pyridine (six-membered) due to the availability of the lone pair. In pyridine, the lone pair is available (not part of the aromatic pi system) to accept an acidic proton. In pyrrole, this is not the case. True or False: Protonation of the lone pair of pyrrole destroys the aromatic pi system and the special stability of aromaticity; thus, pyrrole is much less likely to accept an acidic proton on its N atom. True True or False: Furan and thiophene have two lone pairs on their respective heteroatoms. While one lone pair is involved in the aromatic pi system, the other is in the same plane as the atoms of the ring and is available for protonation. True "Pyrrole-like" When the N atom of an aromatic heterocycle has single bonds only, then the lone pair participates in the conjugated pi system to create aromaticity and is not available to react as a weak base. "Pyridine-like" When the N atom of an aromatic heterocycle is participating in a pi bond, then the lone pair occupies an sp2 orbital in the same plane as the ring and is available to react as a weak base. True or False: Furan, pyrrole, and thiophene are all more reactive than benzene in EAS reactions. True Each molecule reacts with electrophiles to substitute (for a hydrogen) at the C-2 position. Why is substitution preferred at the C-2 position on five-membered heterocycles? The carbocation intermediate that forms during the reaction is delocalized over more atoms (and hence, more stable) when substitution occurs at this position. Azoles It is possible to introduce more than one heteroatom into a five-membered heterocycle. Of the many available structural possibilities, the most important heterocycles are formed by introducing a N atom in place of C-3 in furan, pyrrole, and thiophene. The resulting molecules are known as azoles. Thiazole occurs naturally in thiamin (vitamin B1), a coenzyme required for many biochemical processes essential to human life The inclusion of the N at position C-3 results in a "pyridine-like" N, which is involved in a pi bond. Imidazole A very good base, as the positive charge obtained from protonation of the N at position C-3 can be delocalized via resonance over both N atoms. Imidazole is present in the amino acid histidine and is important in the reactions of many enzymes. Why do heterocycles form the largest class of organic compounds known? Structural diversity in terms of their ring size and the number and identity of heteroatom substitutions. Another reason, is the possibility of fused ring systems. Fused ring system Two (or more) rings are fused together to form a larger molecule; to be fused means that each ring shares two (or more) common atoms as a part of the structure of each ring. Purines Another biologically important class of fused-ring heterocyclic compounds. Purines contain a pyrimidine ring fused to an imidazole ring. Uric acid , caffeine, and theobromine (found in chocolate) are all based on the structure of purine. Biochemically, the structures of adenine and guanine, two of the nitrogenous bases present in DNA and RNA are both purines. Indole a bicyclic, fused-ring compound formed by fusing a benzene ring to the C2-C3 bond of pyrrole Indole is a component in many biologically active compounds including the amino acid tryptophan. Heterocycles cyclic organic molecule where one or more carbon atoms are replaced by heteroatoms Heteroatoms Atoms in an organic compound other than carbon and hydrogen Ex: Oxygen, Nitrogen, Sulfur Two main subgroups of heterocycles 1. aromatic 2. aliphatic (non-aromatic) Pyridine analogue of benzene where one C is replaced by N geometry of pyridine flat/ planar geometry with 120 degree bond angles atomic structure of pyridine sp2 hybridized atoms, 6 P electrons just like benzene resonance structure of pyridine Why does pyridine undergo substitution rather than addition? addition would destroy the aromaticity solubility of pyridine soluble in most organic solvents and completely soluble in water why is pyridine soluble in water? -ability of pyridine to accept hydrogen bonding interactions from water molecules d/t the lone pair of electrons on the nitrogen. - electronegative N creates a relatively strong dipole moment in the pyridine, thus making it an apolar compound overall. BP of pyridine vs benzene? why? -pyridine has a higher BP than benzene even though they have a similar weight -why? dipole/dipole forces Is pyridine an acid or base? weak base will form pyridinium salt when reacted with strong acids Two main reaction types of pyridine? 1. EAS- Electrophilic Aromatic Substitution 2. NAS- Nucleophilic Aromatic Substitution What happens in the EAS of pyridine? a hydrogen is replaced by an electrophile What conditions are needed for pyridine to undergo EAS? very slow and very harsh conditions- need very hot heat and a strong acid Why is pyridine less receptive to EAS than other molecules? ring is partially positive d/t electron withdrawal by the nitrogen What position does an EAS reaction prefer on a pyridine molecule? C3 bc the charge wont put a positive charge on the electronegative nitrogen via resonance Nucleophilic Aromatic Substitution A substitution reaction in which an aromatic ring is attacked by a nucleophile, which replaces a leaving group. -displaces a hydride ion or a halide ion from the ring Why are NAS easier for pyridine than EAS? the positive partial charge on the Nitrogen atom attracts nucleophiles Azine heterocyclic 6-membered rings with 2 or more nitrogen atoms as part of the ring system Diazines 2 nitrogens replacing carbons in a benzene ring 3 isomeric forms of diazines 1. pyridazine N1, N2 2.pyrimidine N1, N3 3.pyrazine N1, N4 pyridazine placement: 1, 2 pyrazine placement 1, 4 Pyrimidine placement: 1, 3 -most important, found in cyotosine and thymine (DNA/ RNA) furan oxygen-based 5-membered aromatic ring pyrrole nitrogen-based 5-membered aromatic ring thiophene sulfur-based 5-membered aromatic ring 5-membered heterocycles furan, pyrrole, thiophene -aromatic/ behave like benzene -EAS reactions -Flat/planar geometry Biggest difference between benzene and membered aromatic rings? The heteroatom of a 5-membered ring contributes 2 electrons (1 lone pair) to the aromatic system while the 6-membered heterocycles' heteroatom only contributes 1 electron to the aromatic system Pyridine or Pyrrole WEAKER base? Pyrrole is a weaker base than pyridine bc pyrrole uses the lone pair from the nitrogen in the aromatic stabilization system. pronating the lone pair of pyrrole would destroy the aromaticity Difference in Furan and Thiophene compared to pyrrole Furan and thiophene have 2 lone pairs instead of one which leaves one lone pair for protonations after the other is used in the aromatic pi system Is pyridine or the 3 5-membered heterocycles more reactive in EAS reactions? Furan, Thiophene, and pyrrole are more reactive in EAS reactions than pyridine what atom number is preferred for EAS substitution on 5-membered heterocycles? substitution at C2 carbocation intermediate that is formed during EAS is delocalized over more atoms and thus more stable when at C2 Azole more than one heteroatom in a 5-membered heterocycle oxazole oxygen at 1, nitrogen at 3 Imidazole nitrogen at 1, nitrogen at 3 Thiazole sulfur at 1, nitrogen at 3 What does the additional Nitrogen on azoles allow for? lone pair on new nitrgoen means there is availability for the molecule to bond to an acidic proton Why is Imidazole a good base? positive charge obtained from the protonation of nitrogen on position 3 can be localized via resonance over both of the nitrogens Imidazole is found in: histidine (amino acid) thiazole is found in: Thiamine (B1 vitamin) fused-ring system a molecule in which two or more rings share two adjacent carbon atoms indole benzene + pyrrole found in amino acid tryptophan purine pyrimidine ring fused to imidazole ring -found in uric acid, adenine and guanine (A & G in DNA)caffeine, theobromine (in chocolate) Show Less
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CHEM219 / CHEM 219 Module 5 Exam Questions & Answers | Latest 2026–2027 Update |
CHEM219 / CHEM 219 Module 5 Exam Questions & Answers | Latest 2026–2027 Update | Principles of Organic Chemistry with Lab | Portage Learning | Verifi ... Show More ed Solutions 2026 / 2027 Academic Year Q: Generic formula for alcohols Answer R-OH Q: phenol Answer hydroxy-substituted aromatic molecules (any compound with an -OH attached to a benzene ring) Q: IUPAC system rules for naming organic alcohols Answer - organic alcohols are named by replacing the suffix of the parent chain of the molecule with the suffix -ol - The parent chain is numbered so as to give the hydroxyl group the lowest possible number. (examples: 1-propanol, and cyclohexanol) - with unsaturated alcohols the -ol suffix comes last and takes priority when numbering the parent chain (2-propene-1-ol) - Molecules with more than one -OH group get a prefix describing the number of -OH groups added to the IUPAC name. (ethane-1,2-diol) Molecules with more than one -OH group polyols Q: IUPAC rules for phenols Answer - the suffix for an alcohol substituted benzene is "phenol" - start the numbering at the OH group (so OH is at the 1 position) (examples: phenol, 3-methylphenol, 2,4-dinitrophenol) Q: Why can alcohols form strong hydrogen bonds? Answer These attractions raise the amount of energy required to vaporize the liquid-phase molecules (boil), which translates into increased boiling point temperatures. Due to the presence of the hydroxyl group, as the O-H bond is highly polarized by the electronegative oxygen atom. This polarization places a + charge on the hydrogen atom and a - charge on the oxygen atom. The polarization in the O-H bond on one alcohol molecule becomes attracted to the polarization in the O-H bond of another alcohol molecule. Q: Why do alcohols have much higher boiling points than other molecules of similar molecular weight? Answer hydrogen bonding between alcohol molecules Q: Alcohol molecules can freely hydrogen bond to other molecules possessing what groups? Answer O-H, N-H, or S-H functional groupings Q: How does the water solubility of alcohol molecules change as the molecular weight changes? Answer Alcohol molecules of lower molecular weight are mostly soluble in water as a result of the ability to hydrogen bond to OH, NH, or SH groups. As the molecular weight or carbon chain length increases, the alcohol molecules become correspondingly less soluble in water. Q: How do alcohols and phenols act as weak acids and weak bases? Answer - acts as an acid by donating the O-H proton as H - acts as a base by accepting H+ using a lone pair on the O atom Q: amphoteric substances Answer Substances that can act as both acids and bases (alcohols and phenols) Q: Why is acid dissociation for most alcohols unfavorable (lies towards the left)? Answer Dissociation produces an alkoxide ion (the conjugate base of an alcohol), which is a very strong base. Q: How can you conduct acid-base reactions that favor the formation of weaker conjugate acids/bases? Answer To promote (favor) the formation of the alkoxide ion, the alcohol can be treated with sodium or potassium metal (Na or K) or a base that is stronger than the RO- ion produced. Q: protonation of an alcohol Answer - A specific type of elimination reaction. In a dehydration reaction, an alcohol molecule will lose H2O to form an alkene. Alcohols undergo a reaction known as dehydration when they When alcohols act as weak bases by using a lone pair on the oxygen atom of the hydroxyl group, alcohols can accept a proton when they are placed in an acidic environment. Q: What is the product of the protonation of an alcohol called? Answer alkyloxonium ion What is a Dehydration reaction for alcohols? Q: What happens during a dehydration reaction for alcohols? Answer are heated with strong mineral acids (like sulfuric or phosphoric). - the alcohol molecule loses the hydroxyl (OH) from one carbon (the α-carbon) and a hydrogen atom (H) from an adjacent (β) carbon. Q: What is the function of an acid during a dehydration reactions? Why does it do what it does? Answer To protonate the the OH group It does this to make it a better (more stable) leaving group because H2O is a neutral while hydroxide ion is strongly basic. Q: What type of mechanism is a dehydration reaction for a sterically bulky tertiary alcohol? Answer E1 mechanism Q: Steps of a dehydration reaction for a tertiary alcohol Answer - the OH group is pronated (the alcohol acts as a base and accepts a proton from the acid solvent onto its OH group) - the OH group disassociates, forming a carbocation - then water, acting as a base, removes a β-hydrogen to form the alkene. - The net result is that H and OH are removed (eliminated) from the original alcohol substrate. - products: an alkene and H3O+ Q: What type of mechanism is a dehydration reaction for a sterically non-bulky primary alcohol? Answer E2 mechanism Q: Why do primary alcohols dehydrate through the E2 mechanism? Answer Because these substrates do not form stable carbocation intermediates. Q: Steps of a dehydration reaction for a primary alcohol Answer - hydroxyl (OH) group is pronated by the solvent - a water molecule (from the solvent?) removes a β-hydrogen. - As the β-hydrogen is removed the bond H-C bond is broken and then there is a C=C bond formed between the β carbon and the α-carbon. - At the same time. the double bond kicks off the H2O molecule from the α-carbon - The net result is that H and OH are removed (eliminated) from the original alcohol substrate. - products: an alkene and H3O+ Q: What is the order of ease of dehydration of alcohol substrates? Answer 3° > 2° > 1° Tertiary alcohols require the least harsh reaction conditions (typically 25% aqueous acid and 60-80°C), whereas 1° alcohols require fully concentrated acid and temperatures approaching 200°C. Q: When can a single alcohol substrate produce more than one alkene product? Answer This occurs when a β-hydrogen can be removed from different carbons to create the C=C in different places on the parent chain. Q: Zaitsev's Rule Answer In cases where more than one alkene product is possible, the major product is always the alkene whose C=C has more alkyl groups attached. The greater the substitution (the number of alkyl groups) attached to the C=C, the more stable the alkene. Q: What type of reaction is it when alcohols are converted to alkyl halides? Answer A substitution reaction Replacing the hydroxyl group with a halogen Q: What are the different halides that can be used for Alcohols -> Alkyl Halides Conversion? Answer - Conversion using Hydrogen Halides (HX) - Conversion using Phosphorus Halides (PX3) - Conversion using Thionyl Chloride (SOCl2) Q: What are the two ways the use of hydrogen halides promotes substitution? Answer 1. The acid protonates the hydroxyl group of the alcohol to make it a good leaving group. 2. The halide ions are good nucleophiles but weak bases, so substitution is promoted over elimination. What is the order of ease for reactivity of alcohols with hydrogen halides? Primary alcohols react much more slowly and require much more harsh reaction conditions. For example, the conversion of 1-butanol to 1-chlorobutane requires the use of Q: What conditions do the reactions of different alcohol structures require? Answer Tertiary > Secondary > Primary alcohols Tertiary alcohols react the fastest under the mildest conditions. Example: The reaction of 2 methyl-2-propanol with HCl. This reaction occurs by an SN1 mechanism (tertiary substrate) and can be performed at room temperature (R.T.) in as little as fifteen minutes. Secondary alcohols react at intermediate rates by either SN1 or SN2 mechanisms, depending on the structure of the specific alcohol. concentrated hydrochloric acid and a catalyst (typically zinc chloride) and strong heating for several hours to accomplish the same conversion. Primary alcohols react via an SN2 mechanism. How can the reaction of a primary alcohol converting into an alkyl halide via SN2 mechanism by influenced by a ZnCl2 solvent? Answer Primary alcohols react via an SN2 mechanism. The hydroxyl group of the alcohol is protonated and then displaced as a water molecule by a chloride ion. Zinc chloride can serve a similar role as that of a proton by accepting a lone pair from the hydroxyl oxygen atom. Zinc chloride also can dissociate to provide more chloride ions into the reaction mixture, thus increasing the concentration of the nucleophile and the rate of the overall reaction. With a Phosphorus trihalide reagent (PX3), which halides can be X? Answer Cl or Br This reaction is particularly efficient as one molecule of PX3 can convert three molecules of alcohol to the corresponding alkyl halide. Which alcohol structures can be converted to alkyl chlorides and bromides using Phosphorus trihalide reagents? Answer Primary and Secondary structures What is the stoichiometric benefit of Conversion using Phosphorus Halides (PX3)? Answer What is a byproduct of the conversion via phosphorus halides? Why is it beneficial for distillation? Answer A byproduct of the reaction is phosphorus acid (H3PO3), which has a rather high boiling point. This makes isolation of the (relatively) low boiling alkyl halide product easy by distillation. What is the molecular formula for the reagent thionyl chloride? Answer SOCL2 What does using Thionyl Chloride (SOCl2) for conversion of alcohols produce? Which type of structures can this conversion using SOCl2 be used on? Answer - used to convert alcohols to the corresponding alkyl chloride. - very efficient for primary and secondary alcohols. What is the advantage of using Conversion via Thionyl Chloride? Answer Although there is no stoichiometric advantage in this reaction (like with PX3), the advantage to this reaction is that the main byproduct (SO2) is formed as a gas and leaves the reaction mixture. Oxidation Answer Oxidation is recognized in organic molecules by increasing the oxygen content (the number of oxygen atoms) or the oxygen character (more bonds to oxygen). What kind of alcohol structures can go through oxidation? primary and secondary alcohols What are the products of oxidation of alcohols? Carbonyl containing compounds: Aldehydes, Ketones, Carboxylic Acids How does the oxidation of primary alcohols differ from the oxidation of secondary alcohols? Primary alcohols are initially oxidized to aldehydes, which can then be oxidized further to carboxylic acids. Secondary alcohols are oxidized to ketones. No further oxidation (outside of combustion, which destroys the molecule) is possible. This is added to a solution of the alcohol dissolved in acetone as the solvent. Chromic acid is a strong oxidizing agent and will oxidize primary alcohols to carboxylic acids without stopping at the aldehyde stage. Secondary alcohols are oxidized to ketones. There are various chemical reagents that can accomplish the oxidation of alcohols to carbonyl compounds. What are some chemical reagents for oxidation? chromic acid (H2CrO4) potassium permanganate (KMnO4) sodium hypochlorite (NaOCl) Jones' Reagent - what is it? What are its disadvantages? The mixture of chromium trioxide (CrO3) with aqueous sulfuric acid. Produces chromic acid (H2CrO4). One obvious disadvantage of using Jones' Reagent is that it is a strong oxidizer and will not permit the synthesis of aldehydes from primary alcohols. What benefit is PCC (pyridinium chlorochromate) for oxidation reactions? PCC will accomplish the oxidation for a primary alcohol to the aldehyde stage and stop there without further oxidation to the carboxylic acid. A disadvantage of using Jones' Reagent is that it is a strong oxidizer and will not permit the synthesis of aldehydes from primary alcohols (it will continue to the carboxylic acid stage). For this purpose, a mild oxidizing reagent known as PCC is used. How do tertiary alcohols react during oxidation reactions? Tertiary alcohols are unreactive in these types of oxidation reactions. Research into the mechanism of these types of oxidations has revealed that the alcohol must have at least one hydrogen attached to the carbon on the hydroxyl-bearing carbon. ethers All ethers are organic molecules in which two alkyl or aryl (R) groups are covalently bonded to a single oxygen atom. The generic formula for an ether is R-O R'. The R groups can be the same (symmetric ether) or they can be different (asymmetric ether). Nomenclature of Ethers and Epoxides Go to Module 5.3 alkoxy substituent an -OR group attached to the parent chain methoxy The name for a substituent attached to the parent chain of just O-CH3 Epoxides Three-membered cyclic ethers, composed of two carbon atoms and a single oxygen. Epoxides are also known as oxiranes. The small, three-membered ring of an epoxide is very highly strained (severe angle strain), and as a result, epoxides are useful in synthesis where atoms or groups can be added to the epoxide molecule using a ring-opening reaction. crown ethers Macrocyclic (large ring) polymeric ethers are known as crown ethers because their rings have a distinct repeating pattern that resembles a crown. Nomenclature for crown ethers The naming conventions for crown ethers follow the pattern "[x]crown-y", where "x" is a number that reflects the ring size, and "y" represents the number of oxygen atoms. The oxygen atoms are usually separated from one another by two carbon atoms. What is the special ability of crown ethers? Crown ethers are a special class of ethers, as they have the ability to solvate cations (+) within the interior cavity of their ring structures. The lone pairs of the oxygen atoms in the ring can bind to cationic species and hold them. The size of the ring controls which cations can fit into the cavity. This phenomenon is important because it allows ionic compounds to be dissolved in relatively non-polar organic solvents. Why do ethers have lower boiling points than that of an alcohol of the same molecular weight? Due to their atomic connectivity, ethers do not have any O-H covalent bonds and, thus, are incapable of forming hydrogen bonds with one another. The lack of intermolecular attraction causes ethers to boil at much lower temperatures than their constitutionally isomeric alcohols. The boiling point of an ether is very similar to a hydrocarbon of corresponding molecular weight What type of hydrogen bonds can ethers do? Although ethers cannot form hydrogen bonding attractions with molecules of each other, the lone pairs of electrons on the oxygen of an ether can form hydrogen bonds to molecules that have O-H, N-H, or S-H bonds as a part of their structure. In other words, ethers cannot donate hydrogen bonds but can accept them from other molecules. Ethers can accept hydrogen bonds from alcohols, and water. What happens to the water solubility of an ether as the size of the R groups of an ether increases? As the size of the R groups of an ether increases, the water solubility of the ether decreases as the hydrocarbon portion of the molecule overwhelms the ability of the molecule to make hydrogen bonds. Describe ethers as solvents Ethers are relatively inert compounds. For this reason, they are often used as solvents for reactions or to prepare solutions containing relatively reactive materials. Most organic compounds dissolve in ethers. Ethers as extraction solvents Used to isolate/collect organic compounds from their natural sources. The low boiling point of ethers makes them easy to remove from an extract. Volatility of ethers Ethers, in general, are volatile (low boiling point). This volatility presents a danger as well - most small ethers are highly flammable and should not be used in a location where sources of open flame are found (such as Bunsen or Fisher burners). Electrically operated heat sources or steam are used to heat ether-based (ethereal) solutions. Long-term exposure to oxygen in air can cause the formation of explosive peroxides in ethers. Why is the dehydration of alcohols to produce ethers limited to the synthesis of symmetric ethers from primary alcohols? If the desired ether is asymmetric, or the complexity of the R groups increases, the overall yield of the desired ether product is reduced. With the goal of forming more complex ethers (especially asymmetric ethers), what is one mode of preparation available but not the most preferred option? addition of alcohols to alkenes During this reaction an alcohol is used as the solvent instead of water and acts as the nucleophile, resulting in the overall addition of H (from the acid catalyst) and -OR (from the alcohol) across the double bond of the alkene, breaking the double bond and forming a more complex/asymmetrical ether. With the goal of forming asymmetric ethers, what mode of preparation preferred? What are the steps? Williamson Synthesis This method uses two steps to produce an asymmetric ether. 1. In the first step, an alcohol is converted to its conjugate base (alkoxide ion, RO-) usually by reacting the alcohol with sodium or potassium metal. 2. The alkoxide is then reacted as a nucleophile in an SN2 displacement, typically on an alkyl halide substrate. The net result of the two reactions is the formation of an ether where R does not = R'. What is necessary about the R and R' groups of a Williamson Synthesis in order for their to be a higher yield of product? The R' group would need to have a smaller steric bulk (primary or secondary), which would allow for the SN2 mechanism in the second step. If the R' group is sterically bulkier than the R group, it would have to go through an E2 mechanism which would have a smaller yield of product. what does "unhindered" mean? Less sterically bulky (primary or secondary strucutres) Although mostly inert, ethers can be forced to react under very specific reaction conditions (typically harsh/extreme conditions). The typical mode of reaction of an ether is .....? Cleavage What is the cleavage reaction of an ether? What type of molecule is used to perform the cleavage? Breaking apart of the ether by severing a C-O bond of the ether by an HX. Typically, ethers react with strong acids and heat to undergo cleavage. If the alkyl groups of the ether are unhindered, what mechanism will be used to sever the C O bond? The C-O bond can be broken by reaction with a halogen nucleophile in an SN2 reaction after protonation of the ether oxygen What happens during a cleavage reaction if the alkyl groups are unhindered? The halogen bonds to the less-hindered R group (creating the alkyl halide), and the oxonium ion is displaced to form an alcohol (containing the larger, more-hindered R group). What happens during a cleavage reaction if the alkyl groups are hindered (tertiary)? If the alkyl groups are bulky/sterically hindered (tertiary), the ether typically cleaves by an SN1 mechanism, as these groups can form the stable carbocation intermediate that defines the SN1 mechanism. In this case, the ether oxygen atom remains with the less-hindered alkyl group and the halide bonds to the more-hindered alkyl group. What are the initial products of the cleavage of an ether using HX? What happens is excess HX is present? The initial products of the cleavage of an ether using HX are one equivalent of alcohol and one equivalent of alkyl halide. If excess HX is present, the alcohol formed via cleavage may react to form another equivalent of alkyl halide. Cleavage reactions can be used to help determine the structure of complex, naturally occurring ethers because the products of the cleavage reaction are smaller and more easily analyzed fragments. Working backward from the fragments, the structure of the original ether can be deduced. What is a peroxyacid (or peracid) and what is it used for? A peroxyacid is analogous in structure to a carboxylic acid but contains an extra oxygen between the carbonyl and hydroxyl group. A reagent used to synthesis epoxides from alkenes. What happens during a epoxidation reaction? An alkene reacts with a peroxyacid to form an epoxide. - an oxygen is transferred from the peroxyacid to the alkene - the C=C p bond is broken and incorporates the oxygen atom as part of a three-membered ring. Why are epoxides more reactive than ethers? Due to the significant amount of ring strain in epoxides, they are much more reactive than regular ethers and undergo reactions through opening of the three-membered ring. What is a common way to open the three membered ring of a epoxides? Treat the molecule with aqueous acid (a mixture of acid and water). What happens during a reaction between epoxides and aqueous acid or alcohols? What is the product? - initial protonation of the epoxide oxygen - followed by a nucleophilic attack of water on one of the epoxide carbons - SN2 where the leaving group remains attached to the other carbon atom of the original epoxide ring The product of an acid-catalyzed ring opening of an epoxide is a diol, specifically a vicinal diol (two hydroxyl groups on adjacent carbons). vicinal diol two hydroxyl groups on adjacent carbons Alcohol Generic formula R-OH, defined by the presence of a Hydroxyl group (-OH). Organic derivatives of water, as one of the hydrogen atoms from the water molecule is replaced by an alkyl group. Phenols Hydroxyl group directly attached to a benzene ring Methyl Alcohol Only H atoms attached to the carbon bearing the-OH group Primary Alcohol one alkyl group attached to the carbon atom bonded to the -OH group Secondary Alcohol Two alkyl groups attached to the carbon atom bonded to the -OH group Tertiary Alcohol Three alkyl groups attached to the carbon atom bonded to the -OH group Boiling Point of Alcohols High due to Hydrogen bonding between the positively charged H and negatively charged O Alkoxide Ion conjugate base of an alcohol, very strong base Water solubility of alcohols As the carbon chain length increases alcohol becomes correspondingly less soluble in water. Alcohols Acidity/Basicity Can act as a weak base (accepting H+ using a lone pair on the O atom) or weak acid (donating the O-H proton as H+) Amphoteric a substance that can act as both an acid and a base Alkyloxonium Ion The conjugate acid of the alcohol is often called a protonated alcohol, Dehydration Loss of water. An alcohol molecule will lose H2O to form an ALKENE. Type of elimination reaction — lose the -OH from one C and H atom from the adjacent C. First step — alcohol acts as a base. Tertiary alcohols - E1 Primary alcohols - E2 All dehydration begins with... Protonation of the alcohol group. Order of ease of dehydration of alcohol substrates... 3>2>1 Tertiary require the least harsh conditions (typically 25% aqueous acid and 60-80 degrees C) whereas primary require fully concentrated acid and temperatures approaching 200 degrees C. If more than one alkene product is possible... The major product is the one whose C=C has more alkyl groups attached. ZAitsev's Rule The production of the more highly substituted alkene as the major product. Alcohols —> Alkyl Halides -Substitution REaction , replacing the -OH with a halogen -Alcohol (R-OH) + Hydrogen Halide (H-X) ——> alkyl halide (R-X) + water (H-OH) -the use of Hydrogen halides promotes the substitution in two ways 1. Acid protonates the -OH of the alcohol to make it a good leaving group 2. Halide ions are good nucleophiles but weak bases so substitution is promoted over elimination Order of Reactivity of Alcohols with HX 3>2>1 Primary Alcohols react via.... (With HX) Sn2 -OH group is protonated and then displaced as a water molecule by a chloride ion Secondary Alcohols react via... (with HX) Sn1 or Sn2 - depending on the structure of the specific alcohol Conversion using Phosphorous Halides (PX3) X= Cl or Br - Alcohol (3R-OH) + phosphorous trihalide (X2P-X) —> alkyl halide (3R-X) + H3PO3 -particularly efficient as one molecule of PX3 can convert 3 molecules of alcohol to the corresponding alkyl halide -byproduct of the reaction is phosphorous acid Conversion using Thionyl Chloride (SOCl2) Alcohol (R-OH) + Thionyl Chloride (Cl-S=O-Cl) —> alkyl Chloride (R-Cl) + SO2 ^ + HCl - very efficient with primary and secondary alcohols d/t the main byproduct (SO2) beig formed as a gas and leaving the reaction mixture. Oxidation to Aldehydes, Ketones and CArboxylic Acids Oxidation - increasing the oxygen content (number of oxygen atoms) or the oxygen character (more bonds to oxygen) -Primary Alcohols —> aldehydes —> Carboxylic Acids -SEcondary Alcohols —>ketones -Tertiary - unreactive Jones Reagent Cromium Triioxide with aqueous sulfuric acid —> Chromic Acid Disadvantage - strong oxidizer and wil not permit the synthesis of aldehydes from primary alcohols Oxidizing agents that convert alcohols to Carbonyl compounds Potassium Permanganate (KMnO4) Sodium Hypochlorite (NaOCl) PCC Oxidation of Alcohols Pyridinium Chlorochromate - oxidizes primary alcohols to the aldehyde stage and stop there without further oxidation to the Carboxylic acid. -Dichloromethane (CH2Cl2) is typically the solvent used for PCC oxidation o alcohols Ether Alkyl or Aryl group that are covalently bonded to a single O atom. Generic Formula : R-O-R' (R groups can be the same - symmetric or different - asymmetric) Epoxides Three-member Ed cyclic ethers - composed of two C atoms and a single O atom. Also known as Oxiranes. Very highly strained (severe angle strain) Useful in synthesis where atoms or groups can be added to the Epoxide molecule using a ring-opening reaction Macrocyclic Large ring polymer ethers Crown ethers - because their rings have a distinct repeating pattern [X]crown-y ; X= ring size ; y= number of oxygen atoms Crown Ethers Can solvate cations within theur interior cavity, size of the ring controls which cations can fit into the cavity, this allows ionic compounds to be dissolved in relatively non-polar organic solvents Properties of Ethers Clear, Colorless, with characteristic odors Lower BP than alcohols with similar molecular weights Cannot H bond Boiling point is similar to a hydrocarbon of corresponding molecular weight Can not form H bonds to each other, but can form H bonds to O-H, N-H or S-H to the lone pair of O As the R groups increase, water solubility decreases Ethers as Solvents Relatively inert Make excellent extraction solvents (used to isolate/collect organic compunds from theur natural sources) Low boiling point Highly flammable Preparation by Addition of Alcohols to Alkenes Williamson Synthesis Two steps to produce an asymmetric ether, in fist step alcohol is converted to its conjugate base, (Alkoxide ion RO-) by reacting the alcohol with sodium or potassium metal. The Alkoxide is then reacted as a nucleophile in an Sn2 displacement, typically on an alkyl halide substrate. Net result is an ether where R does not equal R. Typically primary or secondary only. Cleavage by HX Typical mode of reaction is cleavage (breaking apart of the ether by severing a C-O bond of the ether. Usually react with strong acids and heat. Tertiary - Sn1; ether O remains with the less-hindered alkyl group and the halid bonds to the more hindered alkyl group. Initial products of cleavage of an ether are an alcohol and an alkyl halide. Synthesis of expoxides from alkenes Use peracid (peroxyacid). Forms by transfer of the extra O to the alkene. C=C bond is broken and incorporates the O atom as a part of a 3 membered ring. Peroxyacid Analogous in structure to a Carboxylic acid but contains an extra oxygen between the carbonyl and hydroxy group Reactions of Expoxides with waters and alcohols Epoxides are much more reactive due to their ring strain. A common way to open the ring is to treat it with aqueous acid. Sn2 - initial protonation of the expoxide O , followed by nucleophilic attack of water on one of the epoxide Carbons. Vicinal Diol Product of an acid-catalyzed ring opening of an epoxide. Two hydroxyl groups on adjacent carbons. Aldehydes Presence of a carbonyl group (C=O) with at least one H attached to the carbonyl C and the remaining valence may be another H atom or an alkyl or aryl group. Ketones Presence of a carbonyl group (C=O), carbonyl C is directly connected to two other C based groups. IUPAC aldehyde nomenclature -al (suffix) Parent chain is named based in the number of C in the longest chain containing H C=O(formal group) IUPAC ketone nomenclature -one suffix Parent chain is the longest contiguous chain that contains the Carbonyl group, numbering begins at the end of the chain nearest the carbonyl carbon Nucleophilic Addition Attack of the nucleophile at the positive carbonyl carbon, this attack is typically followed by addition of a proton (hydrogen) to the carbonyl oxygen Dipole-dipole attractions Cause the molecules to associate with the + part of one molecule attracted to the - part of another. Stronger than van der walls forces, but weaker than H bonding. Aldehydes are reduced to... Primary alcohols Ketones are reduced to... Secondary alcohols Hydride transfer reducing agents Most widely used reagent to reduce aldehydes and ketones. They reduce aldehydes and ketones by producing hydride ion (H:-) in solution. Hydride ion is a potent nucleophile and can react with the carbonyl C of an aldehyde or ketone. Ex. Sodium Borohydride (NaBH4) Sodium Borohydride (NaBH4) Advantages - reduces all aldehydes and ketones. Stable and can be used in mixed aqueous systems. Very efficient as one Borohydride can transfer all 4 of its H atoms as hydride ions and reduce 4 carbonyls The difference between most additions of aldehydes and ketones is WHEN the proton gets bonded to the carbonyl carbon... Acidic environment - proton bonds to carbonyl O before the nucleophile attacks which makes the C=O more reactive towards nucleophilic attack and is useful when a weaker (uncharged) nucleophile is used. Basic Environment - the strong (typically negative) nucleophile attacks first, followed by subsequent protonation of the Alkoxide oxygen. Nomenclature of Carboxylic Acids -oic acid Numbering begins with carboxyl carbon atom Show Less
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CHEM219 /CHEM 219 Module 4: (Latest Update 2026 / 2027) Principles of Organic Chemistry with Lab
CHEM219 / CHEM 219 Module 4: (Latest Update 2026 / 2027) Principles of Organic Chemistry with Lab | Questions & Answers | Grade A | 100% Correct – Po ... Show More rtage Learning 2026 / 2027 Academic Year Q: Describe bonding in alkanes ? - Each carbon atom is joined to 4 other atoms by single covalent bonds. - These type of covalent bonds are sigma bonds. A sigma bond results from the overlapping of 2 orbitals from each of the bonding atoms. - Each overlapping orbital has 1 electron, so the sigma bond contains 2 electrons which are shared equally between the bonding atoms. Answer - Each carbon atom has 4 sigma bonds ,( either c-c or c-h bonds ). Q: Describe the shape of alkanes ? - Each carbon atom surrounded by 4 electron pairs - electron pairs repel equally = a tetrahedral shape and bond angle of 109.5 degrees. Answer - The sigma bonds also act as an axes for which the carbon atoms can rotate freely = meaning alkane shape is not rigid and can rotate. Q: Why is fractional distillation possible ? Answer Because the boiling points of alkanes are different - they increase as their chain length increases. Q: London forces act between molecules that are in what ? Answer That are in close surface contact. Q: Effect of chain length on boiling point ? Answer - As the chain length increases, the molecules have a larger surface area = more surface contact between the molecules. - The London forces are greater = more energy required to overcome these forces. Q: The effect of branching on boiling points ? Answer - There are fewer surface points of contact on branched alkanes = fewer London forces = less energy required to overcome these forces. - Additionally, the branches get in the way and prevent the branched molecules to get as close as straight-chained molecules. - This further reduces intermolecular forces. Q: Describe the reactivity of alkanes ? Answer Alkanes do not react with most reagents. Their low reactivity is because their C-C and C-H sigma bonds are strong, and the C-C bonds are non-polar. - The electronegativity between carbon and hydrogen is so similar that C-H bonds can also be considered non-polar. Q: What do alkanes produce during combustion ? Answer They produce CO2 and water, when burnt with a plentiful supply of oxygen. Q: What produces in incomplete combustion ? Answer CO or C ( each with H20 always ) - It occurs only in UV light - its a substitution reaction - as a H atom in the alkane is substituted by a halogen atom. Q: Where does incomplete combustion take place ? Answer Takes place in a closed space = e.g. CAR ENGINE, FAULTY HEATING SYSTEM. Q: Describe the reaction of alkanes with halogens ? Answer Q: Outline first step of radical substitution for the bromination of alkanes : Include reactions : 1. Initiation : Answer When the covalent bond in a bromine molecule breaks down forming 2 bromide radicals under UV light. Br2 --> Br. + Br. Q: Outline the second step of radical substitution for the bromination of alkanes : Include the 2 reactions : Answer 2. Propagation Step 1 : Br. + CH4 --> CH3. + HBr Step 2 : CH3. + Br2 --> CH3Br + Br. - the new bromine radical then reacts with more CH4 molecules - as a CHAIN REACTION. Q: Outline the third step of radical substitution for the bromination of alkanes : Include the 3 reactions : Answer 3. Termination 2 radical collide forming a new molecules with all pairs of electrons. - meaning both radicals are removed from the reaction. Br. + Br. --> Br2 .CH3 + .CH3 --> C2H6 Br. + .CH3 --> CH3Br Q: Explain the limitations of radical substitution in organic synthesis : 1. - Further substitution : - Bromomethane can reacts with another Br. radical - substituting a further H atom to form CH2Br2 - further substitution can continue until all the Hydrogen atoms are gone leaving a mixture of CH3br , CH2Br2 , CHBr3 , CBr4 2. Substitution at different points on a carbon chain : Answer - For longer carbon chained haloalkanes - there will be a mixture of mono-substituted isomers by substitution at different points in the carbon chain. - e.g. pentane will have 3 mono substituted isomers. Q: Organohalides Answer Organic molecules contains Halogen atoms. Ex. Algae, Mollusk, sponges, can be industrially used - solvents, insecticides, herbicides, cleaning fluids, fire retardants, refrigerants. Can also be used as inhaled anesthetic. More important in organic chemistry because of theur reactivity. Q: Two of the most important reaction types typical of organic Halides are.... Answer Substitution Elimination Q: Substitution Reaction Answer Replacing the halogen in a molecule with another atom or functional group. Q: Elimination Answer Removes the halogen and hydrogen atoms from the original substrate molecule creating an unsaturated compound. Q: Alkyl halide Answer Aliphatic hydrocarbons that possess one or more halogen atom substituents. Q: Aryl Halides Answer Aromatic hydrocarbons (benzene rings) with one or more halogen atoms attached to the ring. Q: Steric Bulk Answer Structural substitution surrounding any carbon atom that bears a halogen. Methyl, primary, secondary, tertiary. Q: Primary Alkyl Halide Answer Only on e carbon is directly attached to the carbon bearing the halogen. Q: Secondary Alkyl Halid Answer Two carbons directly attached to the carbon ring bearing the halogen Q: Tertiary Alkyl Halide Answer Three carbons are directly attached to the carbon bearing the halogen Q: Methyl halide Answer Only hydrogen atoms attached to the carbon bearing the halogen Q: X Answer Symbol for generic halogen Carbon will be electron-deficient and thus hold a slight positive charge and slight negative charge on the halogen Q: Polarization of C-H bond Answer Nucleophilic substitution reaction Answer Halogen is replaced (substituted by) a new atom or functional group. Abbreviated Sn Functional Group Interconversion Answer When one type of functional group (alkyl halide) is converted to another by substitution. Substrate Answer Molecule on which the substitution occurs. Leaving group Answer Atom or group of atoms that is replaced by another when substitution occurs Nucleophile Answer A chemical species that seeks positive charge due to the presence of one or more lone pairs present on an atom in the nucleophile Typical Nucleophiles - O,N,S Nucleo = nucleus/positive charge Phile = love There can be negatively charged nucleophiles (more reactive) or neutral nucleophiles. Generic presentation of nucleophile substitution reaction Answer Nucleophile: + Substrate-Leaving group —> nucleophile-substrate + leaving group Unreactive in nucleophilic substitution reactions Answer Aryl and vinyl halides. Substrates in which the halogen is attached to a C that is a part of a multiple bond. Mechanism Answer Term used by organic chemists to describe and explain how reactions happen at the molecular level. Also called "roadmaps" because they describe the stepwise formation of products from the reactant molecules. Two Main Types of Nucleophilic Substitution REactions Answer Sn1 and Sn2 Sn2 -single step (concerted) -nucleophile attacks from the backside of the C-L bond. Nucleophile uses a lone pair of electrons to begin making a bond to the carbon. Simultaneously the bond between the C and the L begins to break. "Backside attack" -Transition state: nucleophile and leaving group are both partly attached to substrate. -L departs from the substrate with the pair of electrons from the C-L bond and nucleophile is fully bonded to the C -Inversion of the tetrahedral geometry occurs. *increasing the concentration of either the nucleophile or substrate will increase the rate of the reaction *2 is used becuae nucleophile and substrate are involved in the only step (key step) *methyl and primary alkyl halide react this way more easily FActors that influence the mechanistic path... of Sn2 -Strength of the nucleophile - SN2 depends on a strong Nucleophile, the more negative, the stronger. -Size of nucleophile - larger are more efficient -Electronegativity of the Nucleophilic atom - the more electronegative, the less nucleophilic -Solvent chosen - they are polar and require polar solvents ; best solvents are polar aprotic solvents Sn1 -two steps -Step 1 - Leaving group leaves first. C-L bond breaks and produces 2 ionic products: carbocation intermediate and a leaving group anion (this step is energy intensive and very slow) known as the rate determining step (RDS) -Step 2 - nucleophile attacks the carbocation intermediate, using a lone pair to form a covalent bond. *no inversion of tetrahedral geometry *produces 50:50 enantiomers. *secondary and tertiary typically react this way Factors that influence the mechanistic path of... Sn1 -nucleophile size, strength , concentration and electronegativity have no effect -solvent chosen - polar protic solvents - they can donate H bonds becuase they have -OH, NH, or -SH froup as part of their structure. Elimination reaction When the structure of the alkyl halide substrate contains one or more hydrogen atoms attached to the carbon adjacent to the carbon bearing the leaving group. Halogen atom is removed, along with H atom from the adjacent C atom to create an alkene. Product - ALKENE -nucleophile acts as a base and removes a H (proton) from a C adjacent to the C bearing the halogen , this C is known as the Beta C and the H associated are called Beta Hydrogens -The C bearing the leaving grou is the alpha C and associated H are alpha H Dehydrohalogenation When the reaction occurs specifically on an alkyl halide substrate. Both H and Halogen are being eliminated from the substrate molecule. E2 -one step -biomolecular -Nucleophile acts as a base and removes the beta H from the beta C, at the same time the electrons from the C-H bond come down tot for a C=C bond and break the carbon halogen bond, releasing a halide ion. E1 -several steps -alkyl halid first undergoes dissociation from the carbocation intermediate. -once formed the carbocation intermediate undergoes elimination by the nucleophile (acting as base) removing a Beta H from a beta C to form the C=C Primary Alkyl Halide (RCH2X) Will react by an Sn2 pathway if a good nucleophile (I-, Br-, RS-, NH3, or CN-) is used. There will be increasing amounts of elimination product from an E2 pathway as the basicity of the nucleophile increases (HO-, RO-). No Sn1 or E1 pathways are possible for primary substrates. Secondary Alkyl Halide(R2CHX) While all four mechanistic pathways are possible, typically these substrates will react by both Sn2 (when weak bases are used) and E2 (when strong bases are used) pathways to give a mixture of substitution and elimination products. Tertiary alkyl halide (R3X) Will react by an E2 pathway when a strong and/or bulky base is used as the nucleophile. When a weak nucleophile is used (or under acidic conditions) a mixture of substitution and elimination products will form by Sn1 and E1 mechanisms. No Sn2 pathway is available for tertiary substrates. Show Less
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CHEM219 / CHEM 219 Module 3: (Latest Update 2026 / 2027) Principles of Organic Chemistry with Lab
CHEM219 / CHEM 219 Module 3: (Latest Update 2026 / 2027) Principles of Organic Chemistry with Lab | Questions & Answers | Grade A | 100% Correct – Po ... Show More rtage Learning 2026 / 2027 Academic Year Q: Characterize each of the following objects as being chiral or achiral: a. Pencil b. Wine Glass c. Baseball Glove d. Orchestra Conductors' Baton e. Scissors Answer a. achiral b. achiral c. chiral d. achiral e. chiral Q: Draw each of the following structures on a piece of paper. Identify any stereo centers in each indication the carbon number corresponding to a stereo center. If there are no stereo centers in a compound state none a. 1,2-dimethycyclohexane b. 2,3,4-trimethylhexane c. 1-bromo-1,2-dichloropropane a. stereocenters at C1 and C2 Answer b. stereocenters at C3 and C4 Q: Question 2 part 2: 2,2 dichloropropane, 1,2 dichloroputane, 2 methylhexane Answer a. none b. one stereocenter at C2 c. one stereo center at C2 Q: Assign priority order (1-4; is greatest priority) to the following four groups for the purpose of deterring R and S configurations at a stereocenter Answer i. 3, 1, 2, 4 ii. 4, 3, 2, 1 Q: Based on the direction of twist of the following groups, assign an R or S orientation S orientation R orientation Answer R orientation Q: question 4 part 2 S orientation R orientation Answer S orientation Q: The Fischer projection formula of the molecule fructose is shown below. How many stereocenters are present in the fructose molecule? What is the maximum number of stereoisomers that could exist for this sugar? Answer a) 3 b) 8 stereoisomers Q: Question 5 part 2. Blood Sugar Answer a) 4 b) 16 Q: Assign an R/S configuration for the following chiral molecule . Explain Answer R configuration because this is a clockwise rotation Q: For each of the following molecules, determine if the C=C is in the E or Z configuration Answer a. E configuration b. Z configuration Q: Question 7 part 2 Answer a. Z configuration b. E configuration a. Which stereoisomers (if any) represents pairs of enantiomers? (list all the pairings that apply) Q: The molecule 2,3-dibromobutane has two stereocenters (C2 and C3) and thus can exist as a maximum of four different stereoisomers. The Fischer projections of these stereoisomers are shown below. Answer the questions which follow. b. Which stereoisomers (if any) represents pairs of diastereomers? ( list all the pairings that apply) c. Which stereoisomers (if any) represent a mess compound? Answer a.C/D are enantiomers b. the pairs of A/C, A/D, B/C, and B/D are diastereomers c. memo compound is A Q: Question 8 part 2 Answer a. a/c and b/d are enantiomers b. a/b, c/d, a/d, b/c are diastereomers c. a,b,c,d are meso compound Answer True Q: Determine if the statements below are true of false regarding pair of molecules shown. They have different boiling points Answer False Q: Determine if the statements below are true of false regarding pair of molecules shown. One rotates plane-polarized light in the opposite direction from the other Q: Determine if the statements below are true of false regarding pair of molecules shown. They have the same density Answer True Q: Determine if the statements below are true of false regarding pair of molecules shown. One rotates plane-polarized light by a different number of degrees than the other Answer False Q: Determine if the statements below are true of false regarding pair of molecules shown. They are non-superimposable mirror images of each other Answer True Q: Briefly explain why it is important for chemists, biologist, doctors and nurses to understand the principle of chirality in organic molecules. Answer It is important for people dealing in medicine because it is very important to know that chiral compounds can change greatly in their characteristics and if not administered carefully can lead to abnormalities. Q: Why is the concept of chirality an important topic to learn to learn in the study of organic chemistry? Answer Chirality is relevant to biology and can be seen in carbohydrates and amino acids. When humans consume drugs the different potencies and effects can be based on the chirality. So it is important to know all of the effects. Q: Assign R/S configuration Answer S configuration because it moves in a counter-clockwise way. Q: Assign priority Answer i) 2, 1, 3, 4 ii) 1, 2, 4, 3 Q: Draw each of the following and identify carbon number to stereo center Answer a) no stereocenter b) C3 stereocenter 3) C2 stereocenter Q: Stereochemistry Answer the study of the three-dimensional structure of molecules Q: Stereoisomers Answer Compounds with the same structural formula and connectivity but with a different 3D arrangement of the atoms in space. Q: Enantiomers Stereoisomers that that are non-superimposable mirror images. Enantiomers have the same connectivity but different orientations (twist) of the four atoms or groups in 3D space. Answer The two different forms of the chiral molecule (the "left-handed" form or a "right-handed" forms) How do the differences caused by steroisomers differ than the differences caused by constitutional isomers. Answer trans-stereoisomers have the substituents on opposite sides/faces of the ring or double bond While the structural differences between stereoisomers are more subtle than those between constitutional isomers, stereoisomerism is often responsible for significant differences in the chemical and physical properties of organic compounds, including the biochemical behavior of many compounds such as drug molecules, amino acids, carbohydrates, and nucleic acids. Several of the human senses, especially smell, are greatly affected by stereoisomerism in organic compounds. cis-stereoisomers have the substituents on the same side/face of the ring or double bond Chirality the concept of "handedness" in an object. Consider the difference between a pair of socks and a pair of gloves. A sock can be worn (interchangeably) on either the left or right foot, but the same is not true for the gloves. A left-handed glove cannot be worn on the right hand and vice-versa. The gloves possess the property of "handedness" (chirality) Observation will reveal that chiral objects are typically not symmetrical (asymmetric), while achiral objects typically exhibit multiple planes of symmetry within the object itself. chiral a molecule that is not superimposable on its mirror image (possesses the property of handedness) achiral A molecule that is superimposable on its mirror image (does not possess the property of handedness) What test can be applied to determine if an object is chiral or achiral? A simple test involves comparing the object and its mirror image for superimposability. Superimposability The ability to align (overlap) two objects so that every unique part of each is in direct alignment with the same unique part on the other. What does it mean when a molecule is a chiral molecule? An organic compound that can exist as two different forms ("left-handed" form or a "right handed" form) Is lactic acid structure chiral or achiral? Attempting to superimpose lactic acid and its mirror image reveals that the two forms cannot be superimposed, and thus, the molecule is chiral, and it exists as two separate forms known as enantiomers (Figure 3.4). No matter how one of the structures is rotated, it is impossible to get all of the atoms/groups in one to align with the same atoms/groups in the mirror image structure. Is the molecule 2-chloropropane chiral or achiral? When the 3D structure of this molecule is drawn, a tetrahedral geometry is observed around the central carbon, similar to that of lactic acid. At first glance, it may not be clear that the molecule is achiral. It is only through the application of the superimposability test that the molecule reveals its achiral nature. The absence of a stereocenter is the reason why molecules like 2-chloropropane are achiral. An analysis of the 3D structure of 2-chloropropane reveals a tetrahedral geometry around the central carbon but only three different types of atoms or groups attached (there were 4 bonds to the carbon but 2 of the groups were identical). The symmetrical nature of the 2 chloropropane molecule comes from having two of the same group on the central carbon - this allows the structure to be superimposed on its own mirror image, and thus, makes the molecule achiral. stereocenter A carbon atom with tetrahedral geometry that is bonded to four DIFFERENT atoms or groups (4 single bonds connected to four different atoms or groups). What is the most common cause of chirality in an organic molecule? The presence of a tetrahedral stereocenter. Identifying a stereocenter in an organic molecule is a way to quickly determine if an organic molecule may possess the property of chirality. This type of carbon is known as a stereocenter, a stereogenic center, or a chiral center. A chiral molecule will almost always possess one (or more) stereocenters. In contrast, most molecules without a stereocenter are not chiral. Stereocenter vs Chirality The stereocenter is the cause of the chirality, while chirality is a property of the molecule as a whole. What are two things that rule out a carbon from being a stereocenter? - if the carbon has more than one hydrogen on it (makes it so there can't be four different groups/atoms) - if the carbon has a double or triple bond (makes it so there cant be four separate bonds and therefore can't have tetrahedral geometry) How is the presence of a stereocenter in an organic structure is denoted? With an asterisk next to the stereogenic carbon Look at the image of 3-methylhexane and explain whether it has a stereocenter and why? Yes, it is chiral because it has a stereocenter. The substituents attached to carbon #3 are a methyl, an ethyl, a propyl, and a lone hydrogen (not pictured). While methyl, ethyl, and propyl are all carbon-based and very similar, they are not identical and that creates a stereocenter. Look up an image of 1-bromo-2-iodopropane and explain whether it has a stereocenter and why? Yes it does have a stereocenter. Only carbon #2 is a stereocenter because the #1 carbon that bears the bromine also bears two identical hydrogens (and thus is not a stereocenter). The presence of the bromine on carbon #1 makes this carbon different from the methyl group (carbon #3) and thus creates the stereocenter on carbon #2. Look at the image of cyclohex-2-ene-1-ol and explain whether it has a stereocenter and why? Yes it does have a stereo center on carbon #1. In the molecule cyclohex-2-ene-1-ol, stereocenters can exist in cyclic structures as well. The #1 carbon in this molecule is a stereocenter because there is a difference in connectivity (different groups) as we go counterclockwise vs clockwise around the ring from the number one carbon. How does the chirality of ibProfin impact the effects of the drug? When ibuprofen is synthesized, the two enantiomeric forms are produced in equal amounts, so you ingest both enantiomers. Only one of the enantiomeric forms is active at relieving pain and the other is inactive. The non-active enantiomer is slowly converted by enzymatic processes in the body to the active form, allowing for an fast and slow effects of the drug. How does the chirality of Thalidomide impact the effects of the drug? One of the enantiomers is therapeutic (treats nausea symptoms) and one of the enantiomers is toxic/has other harmful effects. Thalidomide was given to pregnant women in the late 1950's and early 1960's as a treatment for nausea. While one of the enantiomeric forms was active as a therapeutic, it was not known that the other form caused severe birth defects (teratogenic) in many of the children born to mothers who used the drug. Thalidomide was removed from the market for pregnant women shortly after this discovery. Many of the human senses are subject to the influence of chirality, which sense in particular is sensitive to chirality? Our sense of smell Describe the ways humans can sense the different enantiomers of the Carvone compound? Carvone (a molecule with one stereocenter) forms two mirror-image forms or enantiomers. One form has a sweetish, minty smell, like spearmint leaves. Its mirror image has a spicy aroma with notes of rye, like caraway seeds. Spearmint leaves and caraway seeds are two of the largest natural sources for the extraction of the two isomeric forms of carvone. What does the ability of humans to smell different enantiomers tell about human bodies? The fact that the two enantiomers are perceived as smelling differently is evidence that olfactory receptors in the human nose contain chiral groups, allowing them to respond more strongly to one enantiomer than to the other. Many, but not all enantiomers have unique and distinguishable odors. How do different enantiomers behave compared to each other with melting points, boiling points, density, and refractive index, etc? These physical properties would be the same between the enantiomers. While the behavior of enantiomers in biological systems can be quite different, an interesting note is that the physical properties of pairs of enantiomers are identical. Why can mixtures of enantiomers of a given compound be very challenging to separate from one another? Because the physical properties of pairs of enantiomers are identical (can't boil them to separate etc.) What device is used to determine the percent composition of an unknown mixture of enantiomers? A polarimeter How does a polarimeter work? A polarimeter uses a beam of plane-polarized light to interact with a sample of a chiral compound of unknown enantiomeric composition. The chiral molecules cause the plane of the polarization of the beam of light to rotate. Based on the direction and magnitude of rotation, the % composition (what % R and % S) of the sample can be determined. The rotation of light by individual enantiomers is always equal but opposite. Under carefully controlled and standardized conditions, the measurement of the optical activity of a pure single enantiomer of a compound gives a value known as the specific rotation. What is specific rotation? Specific rotation is the amount a compound rotates light per concentration of the molecule and length of the tube through which the light passes. It is the measurement of the optical activity of a pure single enantiomer of a compound. The specific rotation is a unique property of each enantiomer that can be used to help identify a compound, just as with physical constants like melting and boiling points What is the R/S system or the Cahn-Ingold-Prelog(CIP) system? What specifically does it tell us? The nomenclature system used to name enantiomeric forms of a chiral molecule. This system determines the direction of the "twist" of the groups attached to a stereocenter and incorporates a description of that direction into the name of the compound. What are the R/S designations? One enantiomer will be known as the "R" enantiomer (from the Latin "rectus"), while the mirror image will be known as the "S" enantiomer (from the Latin "sinister"). The R/S designation describes the configuration of the groups around a given stereocenter. What happens to the number of stereoisomers when a molecule has more than one stereocenter? Molecules that possess more than one stereocenter become more complex since increasing the number of stereocenters is associated with increasing numbers of stereoisomeric forms in which the compound can exist. With molecules that possess multiple stereocenters, an important skill is to be able to determine how many stereoisomers will exist for that compound and what the relationships are (how the individual stereoisomers are related to each other). Each stereocenter has a pair of enantiomers. So if a compound has two stereocenters there will be 4 stereoisomers possible. What formula is used to quickly determine the maximum number of individual stereoisomers possible for a chiral compound? 2^n (where n is the number of stereocenters in a compound) The rule says "maximum number", as some structural feature of certain molecules will result in not all of the predicted number of individual stereoisomers existing. 2-bromo-3-chlorobutane stereoisomers This molecule contains two stereocenters. Each stereocenter can exist in either an R or S configuration. Since there are two stereocenters, the permutations are, R, R; S, S; R, S; or S, R,. The structural formulae can be drawn to represent the four structures using wedge-and dash notation. Typically, when representing molecules with more than one stereocenter, the structures are presented with the longest carbon chain written vertically and each stereocenter presented in an eclipsed conformation (using wedge and dash notation) to make the comparisons between the individual stereoisomers more convenient Stereoisomers one and two form a pair of enantiomers. Stereoisomers three and four also form a pair of enantiomers. Thus far, it has been determined that 2-bromo-3-chlorobutane exists as two pairs of enantiomers (four total stereoisomers). What formula is used to find the number of enantiomer pairs for a compound that has multiple stereocenters? (2^n)/2 Where n is the number of stereocenters Cross-pairings of stereoisomers Relationships between the stereoisomers outside of their enantiomer pairs. Example: What is the relationship between stereoisomers one and three? What about one and four? How would we describe any cross-pairing, 1/3,1/4, 2/3,2/4? Diastereomers stereoisomers that are not mirror images of one another (they are cross-pairs, not enantiomers. This can be stated as the relationship between stereoisomers 1 and 3, 2 and 3, 1 and 4, and 2 and 4 is diastereomeric, or that these compounds represent pairs of diastereomers. Compare this to compounds 1 and 2, as well as 3 and 4, which represent pairs of enantiomers (or that their relationship is enantiomeric). Which word would describe the relationship between cis/trans pairs of molecules? They are diastereomers If either the cis or the trans stereoisomer was held up to a mirror, the mirror image would be the same (the mirror image of cis is not trans, and the mirror image of trans is not cis). Thus, since they are stereoisomers that are not mirror images of one another, cis-trans pairs are diastereomers. How do physical and chemical properties of diastereomer pairs differ from properties of enantiomer pairs? While pairs of enantiomers will have the same physical and chemical properties as one another, diastereomers (because they are not mirror images) will not. Diastereomers may have vastly different physical and chemical properties from one another. They may have drastically different melting and boiling points, solubilities, etc. In short, diastereomers behave as two different chemical substances. In practical applications, the separation of mixtures of diastereomers is much easier using common laboratory methods, which take advantage of differences in chemical and physical properties between compounds. In general why does the 2^n rule for predicting maximum stereoisomers not always work? The rule says "maximum number" as there are some structural features of certain molecules that result in not all of the predicted number of individual stereoisomers existing in reality. Why does the 2^n formula not correctly predict the number of stereoisomers for 2,3 dichlorobutane? This molecule has two stereocenters (carbons 2 and 3). Using the rule to predict the maximum number of individual stereoisomers, a maximum possibility of four (2^n = 2^2 = 4) would be determined. After drawing out the 4 stereoisomers we can see that stereoisomers one and two represent a pair of enantiomers, but stereoisomers three and four are different. Although three and four are indeed mirror images of one another, if one is rotated by 180° in the plane of the paper, it becomes superimposable on the other (all the atoms and groups line up exactly on both molecules), so they are the same compound. meso compound A molecule that contains stereocenters but is superimposable on its own mirror image. Due to this, meso compounds are achiral. The compound 2,3-dichlorobutane exists as three different stereoisomers: a pair of enantiomers and a meso compound. What makes a meso compound possible? An internal plane of symmetry. Meso compounds typically have an internal mirror plane of symmetry within their molecular structure. In this molecule, the presence of the two chlorine atoms allows for a plane of symmetry to be created when the chlorines are present on the same side of the carbon chain when written vertically. This internal plane of symmetry allows for this particular stereoisomer to be superimposable on its own mirror image (after a rotation of 180 degrees). Meso compounds would be diastereomers to the enantiomers, and would therefore have different physical and chemical properties. How do the physical and chemical properties of a meso compound compare to the properties of the enantiomers? Meso compounds would be diastereomers to the enantiomers, and would therefore have different physical and chemical properties. Fischer projection A method for representing the structures of chiral molecules in 2D - The carbon representing the stereocenter is usually omitted and is represented instead by the crossing point of horizontal and vertical lines. - The vertical and horizontal lines represent things bonded to the stereocenter. - Horizontal bonds are equivalent to "wedge bonds" (from wedge-and-dash notation). These bonds represent things that project towards the reader (out of the plane of the paper). - Vertical lines are equivalent to "dash bonds" and represent things that project away from the reader (behind the plane of the paper). What is the rule when using Fischer projections for moving a projections? The only "allowed" move is a rotation of 180 degrees in the plane of the paper. No "flips" or rotations other than 180 degrees. Unallowed moves will change the horizontal and vertical bonds and give an incorrect representation of the Fischer projection. Show Less
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CHEM219 / CHEM 219 Module 2: (Latest Update 2026 / 2027) Principles of Organic Chemistry with Lab
CHEM219 / CHEM 219 Module 2: (Latest Update 2026 / 2027) Principles of Organic Chemistry with Lab | Questions & Answers | Grade A | 100% Correct – Po ... Show More rtage Learning 2026 / 2027 Academic Year Q: Two types of reactions for Alkanes Answer Combustion (oxidation) and Radical Halogenation (substitution) Q: What does Combustion reaction produce? Answer CO2 and H2O Q: Is Combustion Endothermic or Exothermic? Answer Exothermic Q: What is exothermic? Answer Heat (energy) is released Q: The greater the number of carbons in an alkane, the _______ the amount of heat released in the combustion reaction Answer GREATER Q: Is the enthalpy (delta H) positive or negative in a combustion reaction? Why? Answer Negative because heat is being released Q: Why is a combustion reaction also called Oxidation? Answer Carbon is combining with oxygen Q: What occurs during a radical halogenation reaction? Answer Halogen atoms replace hydrogen atoms on an alkane molecule Q: Why is Radical Halogenation considered a Substitution reaction? Answer Because halogen atoms substitute hydrogen atoms on the alkane Q: What is the catalyst for Radical Halogenation? Answer Heat or UV Answer More than 1 H atom is replaced by a halogen Q: Halogen radicals in Radical Halogenation Answer Species with a single unpaired electrons that attack the alkane substrate to pull off hydrogen atoms and substitute themselves in their place. Q: Polyhalogenated products Q: Name the 5 "Addition" reactions in alkenes/alkynes Answer Addition reaction Halogenation Hydration Addition of Acids to Alkenes Addition of Hydrogen to Alkenes Q: Name the two oxidation reactions in alkenes/alkynes Answer Oxidation with Potassium Permanganate Ozonolysis Q: Why are addition reactions in alkenes thought of as combunations? Answer Two different molecules join to form a single new compound Q: What happens to the pi bond of the alkene in addition reactions? Answer It is broken Q: What happens to the sigma bond of the reagent in alkene addition reactions? Answer It is broken Q: What does the C atom in addition reactions gain? Answer 2 new sigma bonds Q: How does the geometry of the alkene in addition change? Answer Goes from Trigonal planar to tetrahedral Q: Is the product of alkene addition saturated or unsaturated? Why? Answer Saturated because no new bonds can be made. Q: Halogenation product for alkenes Answer Alkyl Dihalide Q: Why do alkenes readily add halogens? Answer Because it is energetically favorable to do so (due to enthalpy) Q: What happens during a Br Qualitative Test for Alkenes? Answer Br is typically red/brown in color, but when it bonds with alkene, it is dibromoalkane and it is colorless. If you drop Br into a random substance, you will know it is alkene if the color changes to colorless. Q: What happens in the Hydration of Alkenes? Answer Alkenes add a water molecule across the double bond in the presence of an acid catalyst. Q: What is the product of the hydration of an alkene? Answer Alcohol (-OH) Q: Why is an acid catalyst needed in the hydration of alkene? Answer Neutral water molecules are not reactive enough to start a reaction on their own Q: What does H and A stand for with H-A? Answer H = acidic proton A = remainder of the acid What is the qualitative testing in Acid Addition? Q: What is the product of Hydrogenation in Alkenes? Answer Alkane Q: What happens during Hydrogenation of an Alkene? Answer The unsaturation is removed Q: Where does Hydrogenation of an alkene occur? Answer On metal surface Q: Does Hydrogenation of alkenes produce mainly cis or trans stereoisomers? Answer Cis! Q: What is the product in Oxidation w/ KMnO4? Answer Glycol Q: What setting is Oxidation w/ KMnO4 performed under? Answer Basic conditions and relatively cool temps Q: Do Alkenes react readily with aqueous solutions of KMnO4? Answer Yes Q: What is the qualitative test undergone through Oxidation w/ KMnO4? Answer The royal color of the permanganate solution disappears and a brown precipitate of MnO2 appears. This is to distinguish alkenes from alkanes. Q: What is the product of Ozonolysis? Answer Carbonyl groups Q: What occurs during Ozonolysis? Answer Alkene reacts with O3 (Ozone) Q: What is O3's relationship to Oxygen? Please elaborate on the term used Answer Allotrope - Different physical form that an element can exist What is the catalyst in Ozonolysis? Answer Zinc Metal and aqueous acid What happens to the C=C in Ozonolysis? Answer It is cleaved What is the qualitative testing of Ozonolysis? Answer Looking at what atoms or groups are attached to in the carbonyl groups to see where in a chain the double bond is present. This allows for reconstruction of the original alkene. Why do alkenes readily react with oxidizing reagents? Answer High electron density of the double bond What happens in an oxidation reaction of alkenes? Answer The oxidizing agents attack the pi-electrons of the double bond Are aromatic rings stable or unstable? What does this mean? Answer Aromatic rings are stable, which means they have a lack of reactivity What does it mean that aromatic rings are conjugated? Answer Separated by only 1 C-C sigma bond. How are aromatic rings thought of in regards to their conjugated bonds? Answer INFINITE LOOP Repeating pattern of pi - sigma - pi Why do aromatic rings not get involved with reactions? Answer The need for preservation of the pattern. What does EAS stand for? Electrophilic Aromatic Substitution What is an electrophile? Electron-deficient chemical species that seeks electrons What happens during EAS reactions? Electrophile attacks the ring, bonds to carbon to temporarily disrupt the aromaticity. The aromaticity is then restored by chemical species that removes a H atom and donates the electrons from the C-H bone back to the ring restoring the aromaticity. list prefixes for first 10 carbons in order meth, eth, prop, but, pent, hex, hept, oct, non, dec hydrocarbon compounds composed of only carbon and hydrogen parent chain longest continuous chain of carbon atoms alkane (with formula) hydrocarbon containing only single bonds between carbons, CnH2n+2 substituent heteroatom or group of atoms that are attached to the parent chain numerical prefixes for # of identical substituent groups (2-10 in order) di, tri, tetra, penta, hexa, hepta, octa, nona, deca rules for naming alkanes 1. longest continues chain is parent chain 2. number parent chain starting with the end closest to the first branch 3. name using IUPAC rules for substituents IUPAC systematic name order for alkanes locant-(prefix)SubstituentParent in numbering parent chains, if there are two equally long chains... select the chain with the most branches coming off in numbering parent chains, if the first branch point if the same distance from either end of the parent chain... choose the numbering that gives the lower numbers to the most substituents in numbering parent chains, if there are only 2 substituents and both are equidistant from opposite ends of the parens chain... choose the numbering direction so the substituent with the higher alphabetical priority gets the lower locant number solubility and density properties of alkanes NOT soluble in water, low density (< 1g/ml) so floats on top of water melting and boiling points properties of alkanes LOW MPs and BPs due to weak attractive forces between molecules how does branching affect MPs and BPs branching lowers surface area of the molecule, which in turn lowers VDWFs and thus lowering BPs and MPs conformers different shapes of molecules derived from rotations of single bonds staggered conformation H atoms do not overlap in line of sight (more stable) eclipsed conformation heteroatoms overlap with one another (less stable) rotamers conformers that can be swapped with a simple rotation of the C-C bond what conformation do molecules prefer? molecules adapt conformations that minimize repulsion, so likely staggered (zigzag formation) cycloalkane alkane whose carbon skeleton is in a ring how to name cycloalkanes add prefix "cyclo" to the parent chain portion of the name when naming cycloalkanes, if ONE substituent is present... NO locant numbers are added and the substituent name is added in front of the parent name (methylcyclobutane) when naming cycloalkanes, if more than one substituent is present... carbons on the parent ring are numbered, starting with the carbon with the substituent group with the highest alphabetical priority and continuing in the direction that gives the other substituents the lowest locant numbers (1-ethyl-2-methylcyclohexane) angle strain occurs when the actual bond angle in the ring is not what VESPR predicts for the atom's electron geometry angle what is the most stable number of carbons in a chain? Why? 6, because C6 has bond angles that almost match the VESPR prediction of a tetrahedral bond angle torsional strain strain from eclipsed conformations, occurs when a ring is planar and has no choice but to have all carbons on the same plane non-planar conformations slight rotations in C-C bonds to move the carbons from all being on the same plane puckered conformation 2 carbons fold out from the other 2 in a C4 envelope conformation one carbon folds up in C5 chair conformation one carbon tilts up and one on the other end of the ring tiltds down in C6 stereoisomerism different compounds with the same connectivity but different positioning of atoms or substituent groups in 3D space reactivity properties of alkanes typically inert, do not react with most acids, bases, or oxidizing/reducing agents combustion of alkanes properties exothermic, results in CO2 and H2O, the more carbon in the alkane, the more heat is released heterocyclic molecules where at least 1 atom in a ring is NOT carbon (mostly O, N and S) radical halogenation reaction using heat or UV light where a halogen atom replaces a hydrogen atom in an alkane molecule R-H + X-X --> R-X + H-X polyhalogenated products occur when more than one H atom is replaced by a halogen due to excess of the halogen, causing a mixture of all the different possible halogen substituted products list two main types of reactions in ALKANES combustion and substitution (radical halogenation) what causes unsaturation vs saturation unsaturation occurs when the number of H per C is lower than for saturated carbons, and occurs in double bonds as the double bond on the C takes away the possibility of H atoms being able to bond carbocyclic molecules with at least 1 ring of all C functional group group of heteroatoms in a specific pattern attached to an organic molecule that leads to certain reactivity and physical properties electrophilic aromatic substitution substitution where an electrophile (chem substance seeking electrons) replaces an H. instead of addition the (+) electrophile removes an H resulting in the E attached to the ring and an A-H leftover aliphatic hydrocarbons alkanes, alkenes, alkynes aromatic hydrocarbons -arenes, such as benzenes lack of reactivity very stable conjugation double bond separated by 1 sigma bond when 3 or more substituents are present on a benzene the locant numbers are used to describe the position (1,2,4-trimethylbenzene) polycyclic aromatic hydrocarbons more than one benzene ring fused together with each ring sharing 2 or more of the same C atoms in naming monosubstituted benzenes name of substituent group is added to parent name "benzene" (clorobenzene) when 2 substituents are present on a benzene use prefixes to describe location of substituents in relation to one another (o-dichlorobenzene) prefixes for locating 2 substituents on a benzne (o) ortho = 1 carbon away (m) meta = 2 carbon away (p) para = 3 carbon away place letter instead of locant number benzene C6H6 ring with alternating double bonds what reaction is used to pinpoint specific location of double bond? How? ozonolysis, O3 acts like scissors and breaks the double bond apart creating two carbonyl compounds attached to the 2 parts of the molecule how is bromine used in alkene/alkyne reactions if the orange/brown color of the bromine disappears when added to a compound the molecule is an alkene/alkyne typical reaction type for alkenes and alkynes addition reaction where atoms or groups of atoms are added to each carbon in the multiple bond, causing the bond to become single or double two major classes of hydrocarbons aliphatic (alkane, alkene, alkyne) and aromatic (benzene) how does surface area impact MPs and BPs greater surface area means more VDWFs which leads to higher MPs and BPs how to determine if cis/trans isomerism is possible around a double bond if the substituent comes off on the same side it is cis, if on the other side it is trans, if the sides look different it is not possible what are the two qualitative reactions for the presence of an alkene Bromine addition (if color disappears it IS an alkene) AND oxidation with KMnO4 (if purple color disappears and leaves brown precipitate it IS an alkene) why do aromatic rings undergo substitution and NOT addition? the loop of conjugation (pi-sigma-pi) causes great stability, substitution occurs rather than addition because addition would break the stability of the ring list IUPAC steps for naming alkenes/alkynes 1. select parent chain that contains both carbons in multiple bond 2. number locants so the multiple bond has the lower numbers (if equidistant number with 1 closer to 1st branch) 3. indicate multiple bond using lower locant number (2-hexene NOT 3-hexene) in naming alkenes/alkynes if more than one pi bond is present... number the patent chain from the end nearest to the first pi bond is a double C bond and triple C bond are present AND equidistant from the ends number locants... so that the double bond gets the lower numbers how to name cyclic alkenes/alkynes without substituents no locant numbers needed (cyclohexane) how to number cyclic alkenes/alkynes with substituents number so the multiple bond contains number 1-2 and the substituents get the lowest numbers Show Less
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CHEM219 / CHEM 219 Module 1: (Latest Update 2026 / 2027) Principles of Organic Chemistry with Lab
CHEM219 / CHEM 219 Module 1: (Latest Update 2026 / 2027) Principles of Organic Chemistry with Lab | Questions & Answers | Grade A | 100% Correct – Po ... Show More rtage Learning 2026 / 2027 Academic Year Q: On a piece of scratch paper, write out the Lewis Dot Diagram for each of the indicated elements and determine the following for each: Answer a) The number of Lone Pairs the atom possesses in its valence shell.b) The number of Unpaired Electrons the atom possesses in its valence shell.c) The number of bonds the atom will form. Oxygen Carbon Hydrogen Nitrogen Oxygen - a) 2 b) 2 c) 2 Carbon - a) 0 b) 4 c) 4 Hydrogen- a) 0 b) 1 c) 1 Nitrogen - a) 1 b) 3 c) 3 Q: Classify the bonding between the given pairs of atoms as ionic, covalent, or polar covalent. Use the table of electronegativities shown below to help with the classification. a. Br and Br b. K and Cl c. P and Cl d. C and O e. Na and Br Answer a. Br-Br: Electronegativity difference () = 0 = COVALENT (or pure covalent) b. K-Cl: () = 2.2 = IONIC c. P-Cl: ()= 0.9 = POLAR COVALENT d. C-O: ()= 1.0 = POLAR COVALENT e. Na-Br: () = 1.8 = POLAR COVALENT Q: Define the term constitutional isomer. Answer Two (or more) different chemical compounds with the same molecular formula but different connectivity between the atoms in their structural formulae. Q: Explain (using specific evidence) what makes the following two compounds constitutional isomers of one another: Answer Both compounds have a MF of C3H6O - same MF. Compound "a" has a 3-carbon chain with a C=O in the middle. No H atom connected to C of C=O. Compound "b" has a 3-carbon chain with a C=O at the end. There is an H attached to the C of the C=O. Q: What is the relationship between the compounds shown? Are they the same compound, constitutional isomers, or two different compounds that are not related to one another? Explain. Answer Different compounds that are not related. They have different MF - (a) C3H8O, (b) C3H6O. Q: Identify each of the following carbon skeletons as linear (continuous), branched, or cyclic. Answer a) Branched b) Linear (continuous) c) Cyclic Q: On a piece of scratch paper, write out structural formulae for all of the constitutional isomers possible for the MF C3H6F2. How many isomers are possible for this formula? Answer 4 Q: Characterize each of the following structural formula representations as either a dash, condensed, super-condensed, or bond-line formula: Answer a) Super-Condensed b) Condensed c) Bond-line d) Dash Q: Write the molecular formula for each of the compounds whose bond-line formulae are given below. Answer a) C5H10 b) C3H8O c) C4H10O Q: Which bond-line formula shown below represents a constitutional isomer of CH3CH2CH2CH2CH3? Answer (b) Q: Which of the following structures does NOT have the molecular formula C6H14? Answer (d) Q: The structural formula: Has what molecular formula? Answer (c) C7H14 Q: The compound carbon monoxide has the following structural formula: What is the formal charge on the carbon and the oxygen? Show your calculation. What is the overall charge on the molecule? Answer Carbon = 4-(2+3) = -1 Oxygen = 6-(2+3) = +1 Overall = FC Carbon + FC Oxygen = [-1 + (+1)] = 0 Q: For the following example of resonance: Answer Which structure (a or b) represents a "major" resonance contributor to the hybrid? Briefly explain why. Structure "a" is a major contributor. All of the atoms have complete valences and in addition, all of the atoms have a formal charge of zero (All of the atoms are meeting their LDD bonding pattern). Q: Describe how individual resonance structures impact the true structure of a molecule or polyatomic ion. Answer Each contributing individual resonance structure contributes characteristics to the overall hybrid structure of the compound. The hybrid "averages" bond lengths and formal charges by delocalizing them among atoms that share them in each contributing individual resonance structure. Q: On a piece of scrap paper, draw the resonance structure "b" that would result from redistributing the electrons as shown on structure "a" in the diagram below: For your structure "b", complete the table with the information requested: Answer Oxygen: 1 lone pair, 1 single bond, 1 double bond, +1 formal charge. Carbon (1): 0 lone pair, 2 single bond, 1 double bond, 0 formal charge. Carbon (II): 1 lone pair, 3 single bond, 0 double bond, -1 formal charge. Q: Describe the shapes associated with the atomic orbitals associated with the main elements of organic chemistry. Answer S orbitals are spherical (single lobe), while P orbitals are dumbbell-shaped (two lobes). End-on overlap of atomic orbitals leads to the formation of sigma (single) covalent bonds. Sideways overlap of P orbitals leads to the formation of pi (multiple) covalent bonds. Q: Explain how bonds are formed between atoms from the perspective of atomic orbital theory. Answer Atoms form bonds by overlapping individual atomic orbitals from each atom to produce molecular (bonding) orbitals. Q: Explain the two types of atomic orbital overlap that contribute to bond formation in organic molecules. Answer Q: Using the VSEPR method, predict the molecular geometry (shape and bond angle) around the indicated atoms for the following structure: a) C(I) b) C(II) c) N d) S Answer a) C(I) = 4 bond pairs = TETRAHEDRAL, 109.5° b) C(II) = 3 bond pairs = TRIGONAL PLANAR, 120° c) N = 3 bond pairs/1 lone pair = TRIGONAL PYRAMIDAL, 107° d) S = 2 bond pairs/2 lone pairs = ANGULAR/BENT, 105° Q: Catenation Answer The process or preference of an element to link/bond with another atom of the same element. Q: Ionic bond Answer ***formed by the sharing of electrons - electronegativity diff: < 0.4 (zero difference) ***the complete transfer of one or more valence electrons from one atom to another - electronegativity diff > 1.8 (large) Q: (Pure) Covalent bonds Answer Q: Diatomic element Answer When an atom is more stable when bonded to another atom Q: Pure covalent bond Answer ***A bond that forms between atoms of identical electronegativity values. (aka shared electrons) - electronegativity diff < 0.4 (zero) Q: Polar covalent bond Answer ***Bond that occurs when atoms are shared unequally. - electronegativity diff: Between 0.4 and 1.8 Unsaturated compound Answer Molecules that posses one or more double or triple bonds (or a ring) as part of their structure. Isomer Answer Molecules with the same molecular formula but a different structure, and therefore a different shape. - constitutional or structural isomers Formal charge formula Answer FC = group # of element - (dots + dashes) - dots = non-binding electrons (lone pair or single unpaired electrons) - dashes = bonding electrons Resonance structure Answer Two or more structural formula of a molecule with identical arrangements of atoms BUT different arrangements of electrons Major contributor Answer Ideal arrangement/structure Minor contributor Answer Less ideal arrangement/structure Non-contributor Answer - associated with P orbitals only - Pi orbital Arrangement/structure does not match or correlate with correct atoms/electrons in an element. End-on overlap molecules Answer The binding/combination of either S or P orbitals, or both Sideways orbital overlap Answer Valence shell electron pair repulsion (VSEPR) theory A tool for determining the shape around atoms in molecules based on analysis of the patterns of electrons around them. - electrons repel (want to be far apart from each other) Molecular geometry - wedge bond: project out of plane of paper (towards us) - dash bond: project behind plane of paper (away from us) - line bond: rep atoms/groups that remain in plane of paper Cation Becomes positively charged when it loses an electron Anion Becomes negatively charged when it receives an electron The properties & reactivity of an organic molecule are controlled by its composition & shape What is organic chemistry? Branch of chemistry that studies the structure, properties, composition, reaction and synthesis of organic compounds which contain carbon atoms. Catenation Ability of ab element to form bonds with itself, resulting in formation of chains, rings or complex structures. Allows for vats diversity of organic compounds in terms of reactivity and properties Why do atoms form bonds to other atoms? Energetic stability To say an atom is energetically stable means that the overall energy of the atom is lower when in the bonded state than in a non bonded state T/F Lower energy typically means greater stability? Why True b/c the electron configuration of the atom - atomic valence Valence # of bonds an atom will form to fill its valve (outermost) shell. The atom achieves stability from a full valence shell, as there is no desire to make bonds Knowing the valence of an atom is important because it indicates ... How many bonds a given atom will typically form when it combines with other elements to make a molecule What do you look at to figure out how many bonds an element will form LDD Comes from group number Unpaired electrons # of bonds the atom will form # of pairs of electrons LONE pairs or nonbonding , these do not participate in bonding Ionic bonds formed by the complete transfer of 1 or more valence electron from 1 atom to another Cation The atom that loses an electron becomes positively charged Anion The atom that gains an electron, becomes negatively charged Ion Chemical species that possesses a non-zero electrical charge. An ionic bond is the attractive force bt oppositely charged ions - an electrostatic attraction (opposites attract) How does electronegativity (X) increase increases moving towards the right and going up the PTOTE Covalent Bonds share electrons bt elements with little or no difference in their electronegativity - Heat is released when covalent bonds are formed Diatomic Elements a molecule composed of only 2 atoms of the same element. In their natural state, these elements exist as diatomic molecules rather than individual atoms b/c they are more stable in this paired form Key parameters of a covalent bond Bond strength bond length Bond strength determined by how much heat is released when covalent bond forms (atoms lose energy in form of heat), gain stability Chemical term used to describe the energy/stength of a covalent bond is known as bond enthalpy Bond length distance that described the perfect balance bt attraction and repulsion the atoms vibrate around each other at some equilibrium point, neither flying apart or fusing together What determines the number of bonds an atom can form The number of unpaired electrons Do lone pairs bond No Cation Loses electron and becomes positive Ionic bond The transfer of a valence electron to another atom Anion Gains electron and becomes negative Covalent bond Sharing of electrons Pure covalent bond Identity of atoms is the same Polar covalent bond Unequal sharing of electrons EN difference of 0 Pure covalent EN difference of 0-0.5 Covalent EN difference of 0.5-2.0 Polar covalent EN difference above 2.0 Ionic Bond order The number of bonds between atoms: 1 for a single bond, 2 for a double bond, and 3 for a triple bond Unsaturation Lack of hydrogen due to the catenation of carbon Constitutional isomers Same molecular formula, but different connectivity Heteroatoms Atoms other than C and H Condensed formula CH3CH2CH2CH3 Super-condensed formula CH3(CH2)CH3 Formal charge Atoms that do not meet the LDD bonding pattern and possess non-zero charge Calculate formal charge Group number - (Dots + Dashes) Overall charge Sum of formal charges Hybrid resonance The average of all resonance structures What gets changed in resonance Lone pairs -> Multiple bonds OR Multiple bonds -> Lone pairs Never single bonds Major contributors to resonance Completes the valence Orbital Space around nucleus with high probability of finding an electron Node Center of orbital, unlikely to find an electron Which orbitals are in ochem S&P (spherical and dumbell) Combination of orbitals theory A bond between atoms is due to an overlap of their atomic orbitals, resulting in a bonding molecular orbital Sigma bond End on overlap, circular symmetry around bond axis, in hybrid orbitals Pi bond Sideways overlap of orbitals 2 bonding 0 lone Linear, 180 2 bonding 1 lone angular/bent, 107 3 bonding 0 lone trigonal planar, 120 3 bonding 1 lone trigonal pyramidal, 107 2 bonding 2 lone angular/bent, 105 4 bonding 0 lone tetrahedral, 109.5 What do you count double bonds as in VSPER A single pair Linear 180° 2 BE 0 LP Angular (2 total electron pairs) 107° 2 BE 1 LP Trigonal Planar 120° 3 BE 0 BE Trigonal Pyramidal 107° 3 BE 1 LP Angular/Bent (4 total electron pairs) 105° 2 BE 2 LP Tetrahedral 109.5° 4 BE 0 LP Bond Type for 0 difference in EN? Purely Covalent (usually elements to themselves) Bond Type for > 0 but </= 0.5 Covalent Bond Type for > 0.5 by </= 2.0 Polar Covalent Bond Type for >/= 2.0 Ionic Ionic Bond Melting Point Very High Covalent Bond Melting Point Lower than 300 C Ionic Physical State Brittle, Crystalline Covalent Physical State Solid, gas, liquid Covalent Solubility Range of solubilities Ionic Solubility Dissolves readily in polar solvents Ionic Conduction Aqueous solutions conduct electricity Covalent Conduction Aqueous solutions do NOT conduct electricity Formal Charge Formula FC = Group # - (Dots + Dashes) Show Less
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CHEM219/CHEM 219 Module 6 – Principles of Organic Chemistry with Lab | Portage Learning | Updated
CHEM219/ CHEM 219 Module 6 – Principles of Organic Chemistry with Lab | Portage Learning | Updated 2026–2027 | Complete Questions & Verified Answers ... Show More | Grade A 2026 / 2027 Academic Year Q: kekulē model Answer suggested that atoms joined by alternate single and double bonds Q: evidence against kekule Answer 1. lack of reactivity of benzene 2. length of bonds 3. hydrogenation enthalpies Q: lack of reactivity Answer does not undergo electrophilic addition reactions does not decolourise bromine Q: delocalised model of benzene Answer 1. planar, cyclic, hexagonal hydrocarbon 2. overlapping of p-orbitals creates a system of pi-bonds 3. electrons are delocalised Q: phenol acts as... Answer a weak acid Q: phenol vs benzene Answer phenol is more reactive due to the lone pair of electrons from the oxygen p-orbital being donated into the pi-system the electron density of the ring is increased Q: oxidation of aldehydes Answer qto carboxylic acid Q: ketones and aldehydes undergo Answer nucleophilic addition Q: reducing agent Answer NaBH4 sodium tetrahydridoborate(iii) Q: ketone reduced to Answer secondary alcohol Q: aldehyde reduced to Answer primary alcohol Q: reactions of carbonyls with HCN Answer forms hydroxynitriles Q: testing for carbonyl group use 2,4-DNP Answer 1. ad 5cm depth of 2,4-DNP into a test tube 2. add three drops of unknown compound 3. no crystals formed, add a few drops of sulfuric acid 4. yellow/orange ppt indicated presence of a carbonyl Q: reaction with 2.4-DNP Answer condensation reaction Q: tollen's reagent Answer silver nitrate in aqueous ammonia, in presence of aldehyde a silver mirror is produced Q: testing for aldehyde group with Tollen's Answer 1. add 3cm of aq silver nitrate 2. add aq sodium hydroxide until a brown ppt is formed 3. add dilute ammonia until brown ppt dissolves 4. add unknown solution to clean tube 5. add equal vol of tollens Q: silver ions Answer act as an oxidising agent in presence of ammonia, reduced to silver Q: carboxylic acids are classified as... Answer weak acids Q: redox of carboxylic acid and metals Answer form hydrogen gas and carboxylate salt, metal dissolves and effervescence Q: neutralisation of COOH and metal oxides Answer salt and water Q: tests for carboxyl group Answer neutralisation with carbonates Q: naming esters Answer alcohol then carboxylic acid Q: acid anhydride Answer formed from removal of water from two carboxyls Q: esterification Answer alcohol and carboxylic acid to form an ester Q: acid hydrolysis of esters Answer heated under reflux with dilute aq acid produce carboxylic acid and alcohol Q: alkaline hydrolysis of esters Answer reflux with aq hydroxide ions form carboxyl ion and alcohol Q: acyl chloride prep Answer thionyl chloride Q: acyl chloride and water Answer makes carboxylic acid Q: ammonia and amines act as Answer nucleophiles by donating the lone pair of electrons on the nitrogen to an electron-deficient species Q: ammonia and acyl chloride Answer primary amide Q: primary amine and acyl chloride form secondary amide Q: amines behave as bases as the lone pair of electrons can accept a proton Q: amines and salt formation they are bases and they neutralise acids to make salts Q: ammonia in substitution reactions lone pair on the nitrogen atom allowing ammonia to act as a nucleophile Q: amine formation salt and sodium hydroxide Q: for amine formation, essential conditions; 1. ethanol as the solvent preventing further substitution to produce alcohols 2. excess ammonia reduces further sub of amine to form secondary and tertiary amines phenylamine produced reduction of nitrobenzene, heated under reflux with tin and hydrochloric acid esterification of amino acids heating with an alcohol in presence of conc sulfuric acid zwitterions dipolar ion exists at certain pH melting and boiling point will be higher isoelectric point the pH at which the zwitterion is formed amides produced Answer reactions of acyl chlorides with ammonia and amines chiral centre Answer carbon atom that is attached to four different atoms or groups of atoms enantiomers Answer non-superimposable mirror image structures (optical isomers) condensation polymerisation Answer joining of monomers with the loss of a small molecule, usually water polyester Answer monomers are joined together by ester linkages in a long chain to form a polymer -carboxylic acid and alcohol example polyesters Answer terylene poly(lactic acid) terylene Answer monomers: benzene-1,4-carboxylic acid and ethane-1,2-diol uses: clothing and ropes alkali hydrolysis produces: alcohol and acid salt poly(lactic acid) Answer monomer: amino acid benefit: much more biodegradable uses: waste produce bags, internal stitches, disposable utensils polyamindes Answer condensation polymers formed when monomers are joined together by amide linkages -carboyxlic acid/acyl chloride and an amine polyamide examples Answer 1. nylon-6,6 2. Kevlar nylon-6,6 Answer monomers: hexandioic acid and hexan-1,6-diamine uses: clothing and fibres Kevlar Answer monomers:benzene-1,4-diamine and benzene-1,4-dicarboxylic acid uses: bulletproof technique for separating a solid product from a solvent or liquid reaction mixture Answer filtration under pressure filtration under pressure Answer 1. connect one end of the pressure tubing to the filter pump whilst attaching the other end to the Buchner flask 2. fit the buchner funnel to the buchner flask ensuring that there is a good tight fit 3. switch on the tap 4. check for good suction by placing your hand across the top of the funnel recrystallisation Answer the solid product obtained after filtration will contain impurities which can be removed by carrying out recrystallisation. how to recrystallise Answer 1. pour a quantity of the solvent into a conical flask, place over a bunsen burner 2. tip the impure sample into a second conical flask or beaker 3. slowly add the solvent to the impure sample until it dissolves in the solvent 4. allow solution to cool melting point determination Answer determines whether a solid compound is pure melting range Answer difference between the temp at which the sample starts to melt and the temp at which melting is complete impure sample melting point Answer melts over a wide range of temperatures using electrically heated melting point apparatus Answer 1. place the capillary tube containing the sample into a sample hole and thermometer in its hole 2. using rapid heating setting start to heat whilst observing 3. once the solid is seen to melt, record the melting point 4. prep a second sample and place in the melting point apparatus and heat again 5. at melting p, set to low and observe slowly capillary tube setting up Answer 1. sample completely dry and free flowing 2. take glass capillary tube, rotate in bunsen flame 3. fill with crystals melting point using oil bath method Answer 1. set up oil bath 2. attach capillary tube containing sample to thermometer 3. clamp thermometer, end of thermometer and tube should dip into the oil 4. use a micro-burner and record melting point chromatography Answer used to separate individual components from a mixture of substances stationary phase Answer does not move and is normally a solid or liquid supported on a solid mobile phase Answer does move, normally a liquid or gas applications of chromatography Answer analysis of drugs, plastics and forensic science TLC Answer Thin layer chromatography is a quick and inexpensive analytical technique that indicates how many components are in a mixture adsorbent Answer solid substance usually silica, the stationary phase adsorption Answer process by which the solid silica holds the different substances in the mixture to its surface retention factor Answer distance moved by component/ distance moved by solvent retention time Answer in gas chromatography, the time for a component to pass from the column inlet to the detector use of gas chromatography Answer separating and identifying volatile organic compounds present in a mixture gas chromatography stationary phase Answer high boiling liquid adsorbed onto an inert solid support gas chromatography mobile phase Answer inert carrier gas gas chromatography Answer 1. volatile mixture injected into apparatus 2. carrier gas caries components through capillary column 3. components slow down as they interact with the liquid stationary phase 4. the more soluble the component the slower it moved through the capillary column information obtained from a gas chromatogram Answer 1. retention times 2. peak integrations used to determine the concs of components in the sample test for alkene Answer add bromine water, decolourised from orange to colourless test for haloalkane Answer add silver nitrate and ethanol and warm to 50 test for carbonyl Answer add 2,4-dinitrophenylhydrazine forming an orange ppt carbon-13 NMR info Answer types of chemical environments present from the chemical shift the number of carbon environments from the peaks benzene into chlorobenzene Answer chlorine and aluminium chloride benzene to nitrobenzene conc nitric acid conc sulphuric acid reflux at 55 electrophilic substitution benzene with alkyl group alkylation haloalkane anydrous aluminium chloride RTP dry inert solvent benzene with acyl group acylation acyl chloride anyhrous AlCl3 reflux 50 dry inert solvent nitrobenzene to phenylamine tin conc HCl reflux reduction phenylamine to benzene diazonium nitrous acid HCl keep below 10 diazotisation benzene diazonium to phenol water warm above 10 nitrile to carboxylic acid hydrolysis dilute nitric acid amide to carboxylic acid hydrolysis acyl chloride to amide excess ammonia low temp addition-elimination alcohol to alkene conc sulphuric acid heat elimination nitrile to amine reduction LiAlH4 haloalkane to amine excess alcoholic ammonia reflux amide to amine reduction carboxylic acid to acyl chloride 1 PCl5 dry conditions acyl chloride to carboxylic acid cold water addition-elimination acyl chloride to ester reflux in dry anhydrous conditions addition-elimination with alcohol acyl chloride to N-substituted amide anhydrous amine addition-elimination alkane to haloalkane free radical sub UV light radicals alkene to haloalkane hydrogen halide room temp electrophilic sub alcohol to aldehyde sulphuric acid and potassium dichromate distill oxidation alkene to alkane hydrogen nickel catalyst hydrogenation alkene to alcohol steam 300c 60atm H3PO4 catalyst hydration aldehyde to alcohol NaBH4/ sodium borohydride aq/alcoholic reduction nucelophilic addition alcohol to carboxylic acid sulphuric acid/ potassium dichromate refluc excess oxidising agent oxidation haloalkane to alkene KOH in ethanol heat elimination ketone/aldehyde to hydroxynitrile potassium cyanide dilute acid reflux nucleophilic addition carboxylic acid to acyl chloride SOCl2 dry condition carboxylic acid to ester alcohol and acid catalyst reflux pKb strength of base smaller=stronger Kb strength of base larger=stronger electron releasing more basic CH3 groups electron withdrawing less basic calculate isoelectric point pI given as the average of the pKa's that involve the zwitterion Show Less
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CHEM219/ CHEM 219 Final Exam – Principles of Organic Chemistry with Lab | Portage Learning
CHEM219/ CHEM 219 Final Exam – Principles of Organic Chemistry with Lab | Portage Learning | Updated 2026–2027 | Complete Questions & Verified Answer ... Show More s | Grade A 2026 / 2027 Academic Year Q: The speed of a wave (c) is the product of its frequency (ν) and wavelength (λ). Answer E = hv = h x c / λ Q: nm to m or m to nm Answer 1 m / 10^9 nm or 10^9 nm / 1 m Q: What is the maximum number of electrons that can have the quantum numbers n = 3, ℓ = 2, mℓ = -2? Answer The Pauli exclusion principle states that no two electrons in a given atom can share the same set of four quantum numbers (n, ℓ, mℓ, ms). This set of quantum numbers contains three quantum numbers, with the only missing quantum number being ms, which can take on the values +½ and -½. Therefore, this set of three quantum numbers represents a single atomic orbital, which can contain two unique electrons: one with ms = +½ and one with ms = -½. Q: An exothermic reaction causes the surroundings to Answer An exothermic reaction transfers energy from the system to the surroundings. That tells us the surroundings will get warmer. Q: A theory is another word for a(n) _________. Answer A theory or model is a well established explanation of a phenomenon based on a series of facts and a body of evidence. Q: What is the definition of a natural law? Answer A scientific law summarizes an observable behavior. Q: The skeletal structure of a complex organic molecule is shown below. Determine the number of sigma (σ) and pi (π) bonds in the molecule. Answer Remember a single bond = 1 σ; a double bond = 1 σ + 1 π; a triple bond = 1 σ + 2 π. This molecule contains 6 double bonds, so there are 6σ and 6π. There are 28 single bonds, so there are 28 σ. This is a total 34σ and 6π. Q: strontium phosphate Answer Sr₃(PO₄)₂ Q: Which of the following statements is true? Answer One driving force in the vaporization of a liquid is an increase in disorder (entropy). Gas molecules are more disordered than liquid molecules. Adding a non-volatile solute to a liquid also increases the disorder of the liquid molecules, so the difference in disorder between the liquid and gas phases is not as great as with a pure substance. Therefore the tendency to vaporize is not as great for the solution as it is for the pure liquid, resulting in a lower vapor pressure for the solution. Q: Which of the following aqueous solutions would have the highest boiling point? A) 1.0 m NaNO3 B) 1.0 m HF C) 1.0 m C₆H₁₂O₆ D) 1.0 m CaCl2 Answer The dissolved solute will raise the boiling point. The more "things" that are dissolved (ions or molecules), the higher the boiling point will be. The CaCl₂ will break up into one Ca²⁺ ion and two Cl⁻ ions and there will be a concentration of 3.0 m of "things" in solution. The other choices will have fewer "things" in solution and will raise the boiling point less. Q: Which one of the following aqueous solutions would have the highest freezing point? A) 1.0 m NaNO3 B) 2.0 m CH3OH C) 1.0 m C₆H₁₂O₆ D) 1.0 m CaCl2 Answer The dissolved solute will lower the freezing point. The more "things" that are dissolved (ions or molecules), the lower the freezing point will be. Since C₆H₁₂O₆ is a molecule, it will not break apart and there will only be a concentration of 1.0 m of molecules in solution. It will lower the freezing point less than all the other choices. There will be fewer "things" in solution and this will lower the freezing point less than the other choices. Q: isoelectronic ions Answer ions containing the same number of electrons Q: Which of the following bonds is the most polar? Answer Elements that are located far away from each other on the periodic table have larger electronegativity differences and therefore make more polar bonds. Of all the element pairs listed, Rb and Br are the farthest apart. Q: Three blocks of the same shape and size are placed in front of you. Block A has a mass of 3.0 g, block B is 5.0 g, and block C is 10.0 g. Which has the higher density? Answer Density is the ratio of mass to volume. Since the volume is constant between all the blocks, then the block with the highest mass will have the highest density. Q: Density equation mass/volume Answer dRT = PM Q: The solubility of a gas in a liquid generally A) increases with increasing temperature. B) increases with decreasing temperature. C) increases with increasing pressure. D) both (a) and (c). E) both (b) and (c). Answer E) both (b) and (c) Q: Which of the following properties, in general, increase as we move left to right across a period in the periodic table? 1. atomic radius 2. ionization energy 3. metallic character A) 1 only B) 2 only C) 3 only D) 1 and 2 only E) 2 and 3 only Answer B) 2 only Q: All the following statements concerning a sample of oxygen gas at 1.00 atm pressure are true EXCEPT A) the molecules are in constant rapid random motion. B) the pressure exerted by gaseous oxygen is due to the impact of the molecules with the walls of the container. C) the average kinetic energy of the gaseous oxygen is inversely proportional to the absolute temperature of the gas. D) collisions between the gaseous molecules are elastic. E) the volume occupied by the oxygen molecules is negligible compared with the size of the container. Answer C) the average kinetic energy of the gaseous oxygen is inversely proportional to the absolute temperature of the gas. Q: A bond in which an electron pair is unequally shared by two atoms is A) ionic. B) polar covalent. C) nonpolar covalent. D) coordinate covalent. E) dipolar. Answer B) polar covalent. Q: Which of the following statements is (are) true? 1. An excited atom can return to a higher energy level by emitting light energy. 2. An atom can be excited to a higher energy level by absorption of light energy. 3. The frequency and wavelength of light are inversely proportional. A) 1 only B) 2 only C) 1 and 3 only D) 2 and 3 only E) 1, 2, and 3 Answer D) 2 and 3 only Q: Solvent Answer A liquid substance capable of dissolving other substances Q: Solute Answer A substance that is dissolved in a solution. Q: Solution Answer A homogeneous mixture that forms when one substance dissolves another. Q: The measure of the attraction that an atom has for the electrons in a chemical bond is called A) electron affinity. B) ionization energy. C) electronegativity. D) hybridization. E) London forces. Answer C) electronegativity. Avogadro's Law Answer equal volumes of gases at the same temperature and pressure contain equal numbers of molecules Boyle's Law Answer Boyle's Law states that at constant temperature and moles, pressure and volume are inversely proportional. Mathematically this is written as: PV = PV Gay-Lussac's Law Answer the pressure of a gas is directly proportional to the Kelvin temperature if the volume is constant Charles' Law Answer the law that states that for a fixed amount of gas at a constant pressure, the volume of the gas increases as the temperature of the gas increases and the volume of the gas decreases as the temperature of the gas decreases Combined Gas Law Answer the relationship between the pressure, volume, and temperature of a fixed amount of gas Ideal Gas Law Answer PV=nRT R=.08206 If 5.00 g of Gas A and 5.00 g of Gas B are mixed in the same container, and the partial pressure of Gas B is determined to be twice that of Gas A, what do we know about the gases? Answer in terms of KE Volume decreased, wall area decreased = increased pressure If Gas A has half the partial pressure of Gas B, this indicates that there are fewer moles of it at the same mass, and therefore Gas A has twice the molar mass of Gas B mol fraction and partial pressure Answer the formula for both Amonton's Law Answer if the volume of a gas is held constant, increasing the temperature of the gas increases its pressure. Boyle's Law Answer Avagadro's Law Answer in terms of KE Container pressure constant, more gas molecules added = increased volume Dalton's Law Answer The total pressure of a mixture of gases is the sum of the individual pressures (Ptotal=P1+P2+P3...) The kinetic energy (KE) of a particle of mass (m) and speed (u) is given by Answer KE = 1/2 mu^2 The KE avg of a collection of gas molecules is also directly proportional to the temperature of the gas and may be described by the equation Answer KEavg = 3/2 RT Kinetic Molecular Theory The Kinetic Molecular Theory states: ⋅⋅There is no attraction between the gas particles. ⋅⋅The volume available to the gas particles is equal to the volume of the container. ⋅⋅The measured pressure is from collisions of the gas particles with the walls of the container. ⋅⋅The average kinetic energy is proportional to the temperature of the system. Which of the following gas samples have the greatest average molecular speed at 25°C? Speed of individual gas molecules is inversely proportional to the molar mass. CH₄ has a molar mass of just over 16 g/mol and is the smallest of the gases listed. Therefore it has the fastest molecular speed. What is the difference between effusion and diffusion? Effusion is through a pinhole, and diffusion is through open space. Under what conditions are gases most likely to behave ideally? Gases are more likely to behave as ideal gases at low pressures and high temperatures. Particles are moving faster and are farther apart, therefore they are less likely to interact with each other The phrase 'like dissolves like' refers to "Like dissolves like" refers to the fact that polar molecules dissolve polar molecules, which both have polar and perhaps hydrogen bonding intermolecular forces, while nonpolar molecules dissolve nonpolar molecules, which generally only have dispersion intermolecular forces. Which of the following factors affect the solubility of a gas in a liquid solvent? l. Pressure II. Temperature III. Identity of gas The solubility of a gas in a liquid solvent is dependent on the nature of the gas, the temperature and the pressure. Generally, the solubility of a gas in a liquid solvent increases with lower temperatures and high pressure. Forming solution A from liquid B and liquid C is endothermic. Increasing the pressure above the solution will Since the solution does not contain any gases, and since liquids are incompressible, then a change in pressure will have no effect on the solution process. Which of the following statements is true about the solubility of N₂ (g) in CH₃OH (l)? Henry's Law states that the higher the partial pressure of the gas, the more soluble it will be in the solvent. This is because there are more molecules of the solute available to dissolve in the solvent. Hypertonic A solution containing a higher concentration of solutes than inside a red blood cell Isotonic A solution that matches the concentration of solutes in cells Hypotonic A solution that contains a lower concentration of solutes than inside the cell Henry's Law the solubility of a gas in a liquid is directly proportional to the partial pressure of that gas on the surface of the liquid The predicted van't Hoff factor for a calcium chloride solution, CaCl₂(aq), is When the strong electrolyte CaCl₂ dissolves, it breaks up into one Ca²⁺ and two Cl⁻ ions. That gives a van't Hoff factor of 3. At a particular temperature, the solubility of H₂ in water is 0.140 M when the partial pressure is 1.20 atm. What partial pressure (in atm) of H₂ would give a solubility of 4.95 M? 42.4 atm C = kP --> c12/c1 = p2/p1 The Henry's law constant at 25.0 °C for N₂ in water is 0.00061 M/atm. What is the solubility of N₂, in molarity units, in 1.0 L of water when the partial pressure of N₂ is 2.4 atm? 0.0015 M C= kP k= M/atm p= atm C = M (NH₄)₂SO₄ has a van't Hoff factor of i = 2.3. What is the concentration of particles in a 0.7801 M solution of (NH₄)₂SO₄? 1.8 M 2.3 x 0.7801 = 1.8 M = ( i ) x ( M ) What is the molarity of ions in a 0.425 M solution of Li₂SO₄ assuming the compound dissociates completely? 1.28 M When an ionic compound dissociates completely, the ions are separated from each other and surrounded by water molecules. In this compound, the two lithium ions separate from the sulfate ion 3 × 0.587 M = 1.76 m A solution is made by dissolving 2.5 mg sodium fluoride (NaF) in 1.5 L of water at 20.0°C. What is the fluoride ion concentration in ppm of the resulting solution, given that NaF is 45.0% fluoride ion by mass, and the density of water of 1.00 kg/L? 2.5 x 45/100 = 1.125mg weight of ion / weight of water = ppm so, 1.5L = 1.5 Kg 1.125mg / 1.5 kg = 0.75 A solution is made using 175.7 g of hexane (MM = 86.18 g/mol) and 200.0 g of octane (MM = 114.2 g/mol). What is the molality of the hexane in the solution? m = (W g of solute / Molar mass of solute) (1000 / W g of solvent) (175.7g / 86.18g/mol) ( 1000 / 200g) = 10.19m A solution is made using 163.7 g of dimethyl ether (MM = 46.07 g/mol) and 90.0 g of methanol (MM = 32.04 g/mol). What is the mole fraction of the dimethyl ether in the solution? find mol of dim & methanol dim mol / dim mol + methanol = mol fraction Which of the following aqueous solutions would have the highest vapor pressure? According to Raoult's Law, the vapor pressure of a solution is proportional to the mole fraction of solvent, and therefore, inversely proportional to the total solute concentration. So, the lowest molarity of ions will have the highest vapor pressure. Since ionic compounds dissociate in aqueous solution and molecular compounds do not, the total concentration of ions is lowest in CH₃OH (0.10 M). The other solutions (all ionic) have total solute concentrations greater than 0.10M. Volatile Having a significant vapor pressure at a given temperature osmotic pressure equation π = iMRT Which of the following ions will contribute most to elevating the boiling point of H₂O? All will contribute equally. Because boiling point elevation is a colligative property, it depends only on the concentration of solute, not the type of solute. All will contribute equally. Because boiling point elevation is a colligative property, it depends only on the concentration of solute, not the type of solute. Vapor pressure describes the tendency of a substance to change from the liquid to the gas phase, so substances with weaker intermolecular forces will have higher vapor pressures. A substance's boiling point is also indicative of the strength of the intermolecular forces, with weaker intermolecular forces resulting in lower boiling points. Because acetone has the lowest boiling point of the options given, it has the weakest intermolecular forces, and will therefore have the highest vapor pressure. diffusion Diffusion is the movement of a substance from an area of high concentration to an area of lower concentration. In this picture, the purple substance moves from a concentrated area to become dispersed throughout the aqueous solution. osmosis Osmosis is the movement of solvent molecules (often water) through a semipermeable membrane from a less concentrated solution into a more concentrated one resulting in similar concentrations on each side of the membrane. When an electrolyte solution (such as NaCl) is added to ice, the ions have ______ with water molecules and thus ______the ability of the water molecules to form a solid ice structure. When an electrolyte solution (such as NaCl) is added to ice, the ions have strong intermolecular interactions with water molecules and, thus, decrease the ability of the water molecules to form a solid ice structure. A strong intermolecular attraction between the ions and water can prevent water molecules from packing tightly with each other. CaCl₂ is often used to melt ice on sidewalks. Calcium chloride is more effective at melting ice than NaCl. Choose the best explanation for this observation. CaCl₂ dissociates into three ions increasing the concentration of solute species in solution. The ions have strong intermolecular interactions with water molecules and, thus, decrease the ability of the water molecules to pack tightly with each other. The more ions present, the harder it is to crystallize water into ice. _________ is a measure of the tendency of a material to change into the gaseous state Vapor pressure is a measure of the tendency of a material to change into the gaseous state. The molecules are moving rapidly and if they have enough energy they will escape from the liquid. The boiling point of a liquid is the temperature at which its vapor pressure is _______ the pressure of the gas above it. A liquid with strong intermolecular attractions will have a _______ vapor pressure and a higher boiling point The boiling point of a liquid is the temperature at which its vapor pressure is equal to the pressure of the gas above it. A liquid with strong intermolecular attractions will have a low vapor pressure and a higher boiling point. What is the strongest intermolecular force in an aqueous sodium chloride solution? The strongest intermolecular force in an aqueous sodium chloride solution is ion-dipole. The oxygen of water is partially negative and attracted to the positively charged sodium ions. The hydrogen atoms of water have a partially positive charge, which is attracted to the negatively charged chloride ions. The intermolecular force between the water and the ions in solution is stronger than the intermolecular force between two water molecules. The presence of the solute (NaCl) will cause the vapor pressure to ______ and will ______ the boiling point. The intermolecular force between the water and the ions in solution is stronger than the intermolecular force between two water molecules. The presence of the solute (NaCl) will cause the vapor pressure to decrease and will increase the boiling point of the solution. Given that water's freezing point is 0.00ºC and the freezing point depression constant (Kf) is 1.86 ºC・kg/mol, calculate the freezing point depression for a 3.00 molal solution (moles/kg) of NaCl in water. Assume ideal behavior of the ions. The following solution may contain one or more values that are different from the problem provided to you, however, the steps to solve the problem are the same. ΔT = i × Kf × m i = number of dissociated ions Kf = 1.86° m = 3.00 molal solution The boiling point of a liquid is the temperature at which its vapor pressure is _______ the pressure of the gas above it. The boiling point of a liquid is the temperature at which its vapor pressure is equal to the pressure of the gas above it. Which of the following substances would have the greatest dispersion forces? Dispersion forces arise from instantaneous changes in electron density, so compounds with more electrons tend to have greater dispersion forces. Since I₂ has the most electrons of the options given, it has the greatest dispersion forces. Which of the following would exhibit hydrogen bonding in a pure substance? Hydrogen bonding results when a hydrogen atom is covalently bonded to the highly electronegative N, O, or F atoms, resulting in a large partial positive charge on the H atom. Since CH₃CH₂OH is the only option with H bonded directly to one of these atoms (O), it would exhibit hydrogen bonding. immiscible liquids that are not soluble in each other (ex: oil and water) miscible Describes two liquids that are soluble in each other Dispersion forces are due to temporary dipoles Polarizability refers to the ease with which the electron cloud of an atom or molecule can be distorted For a molecule to exhibit dipole-dipole interactions, it must have a permanent dipole moment Which combination of properties would be expected to lead to the most viscous liquid? Viscosity is defined as a liquid's resistance to flowing, so compounds with stronger intermolecular forces will have higher viscosities. High temperature provides molecules with enough energy to overcome attractive forces, therefore, low temperatures lead to more viscous liquids. Molality equation moles of solute/kg of solvent (mol/kg) Clausius-Clapeyron Equation The equation below can be used with just two measurements of vapor pressure and temperature Raoul's Law a law stating that the partial pressure of a solvent over a solution, Pa, is given by the vapor pressure of the pure solvent, POa, times the mole fraction of a solvent in the solution, Xa: Pa = XaPOa Show Less
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CHEM219/CHEM 219 Module 8 – Principles of Organic Chemistry with Lab | Portage Learning | Updated
CHEM219/ CHEM 219 Module 8 – Principles of Organic Chemistry with Lab | Portage Learning | Updated 2026–2027 | Complete Questions & Verified Answers ... Show More | Grade A 2026 / 2027 Academic Year Q: Polymer Answer large molecule made by repetitive linking of smaller units (monomers) Q: Macromolecule Answer very large molecule composed of thousands of covalently bonded atoms (ex: polymer) Q: two ways polymers are made Answer 1. natural (in nature) 2. synthetic (in lab) Q: examples of natural polymers Answer rubber, carbs: starch & cellulose, proteins, nucleic acids DNA, RNA Q: examples of synthetic polymers Answer nylon, teflon, styrofoam, polyethylene, Dacron, Q: 3 main ways to differentiate polymers Answer 1. method of formation 2. final composition 3. stereochemical orientation Q: Two types of Synthetic polymers Answer 1. chain-growth 2. step-growth Q: chain growth polymers are also know as: Answer addition polymers Q: How are chain growth polymers made? Answer made by addition of one monomer unit to another in a repetitive pattern Q: chain growth polymerization Answer A polymerization involving sequential addition to monomers that are unsaturated (C=C) or have some other reactive functional groups (particularly ethylene and derivatives) Q: what 2 things stops chain growth polymerization? Answer 1. intervention 2. consumption of all available monomers Q: Teflon Answer chain-growth polymer: polytetrafluoroethylene monomer: F2C=CF2 nonstick coating, goretex, electrical insulator, chem-resistant coating Q: Saran Answer chain-growth polymer: polyvinylidenedichloride monomer: H2C=CCl2 cling-wrap Q: Polypropylene Answer chain-growth polymer: polypropylene monomer: H2C=CHCH3 carpet fibers, car parts, toys, packaging, houseware Q: Orlon, Acrilan, Creslan Answer chain-growth polymer: polyacrylonitrile monomer: H2C=CH(CN) textiles/fibers, carpets, upholstery Q: Polyvinyl Acetate Answer chain-growth polymer: polyvinyl acetate monomer: H2C=CH(OCOCH3) elmers glue, silly putty, latex paints Q: Polyvinyl alcohol Answer chain-growth polymer: polyvinyl alcohol monomer: H2C=CH(OH) eye med- artificial tears Q: Plexiglass (Lucite) Answer chain-growth polymer: polymethylmethacrylate monomer: H2C=C9CH3)COOCH3 clear plastic sheets , blocks, and tubing Q: the final polymer retains all of the atoms of the monomer Answer the final polymer retains all of the atoms of the monomer Q: step growth polymerization Answer formed by the reaction between 2 different functional groups on different monomer molecules with the accompanying loss of some small molecule (typically water) Q: The defining characteristic of step-growth polymers Answer The final polymer chain does NOT include all the atoms initially present in the monomer molecules Q: step-growth polymers also known as: Answer condensation polymers Q: functionality of step-growth monomers Answer typically di or polyfunctional Q: appearance of monomers in step-growth polymerization Answer alternating order in the final polymer chain Q: how step-growth polymers generally grow Answer by carbon-heteroatom bond formation Q: how chain-growth polymers generally grow Answer carbon-carbon bond formation Q: Polyamide (Nylon) Answer formed by combining 1,6-diaminohexane (amine) with 1,6-hexandioic acid (carboxylic acid) amine functionality reacts with carboxylic acid functionality to form an amide with a corresponding loss of a water molecule naturally occurring step-growth/ condensation polymer examples Answer cellulose, polypetide chains, beta-Hydroxybutyric acid Lexan Answer step-growth polymer: polycarbonate eye glasses, auto parts, drinking glasses Kevlar Answer step-growth polymer: polyamide body armor, tires, helmets step-growth polymer: polyester Dacron, Mylar Answer eletric/thermal insulation, helium balloons, artificial limbs three main mechanisms for addition/ chain-growth polymerization Answer 1. free radical 2. cationic 3. anionic For all three main addition mechanisms, how does polymerization begin? Answer (initiation) begins by creating a reactive intermediate that starts the chain reaction free-radical addition polymerization Answer a monomer reacts with a free-radical initiator to create a free-radical free-radical Answer an atom or a group of atoms that has one unpaired electron radical initiator Answer a reagent that creates radicals, has relatively weak covalent bonds which can be homolyzed 3 main characteristics of free-radicals Answer 1. electrically neutral 2. quite reactive and reacts quickly to pair up the lone electron 3. formed from radical initiators Homolyzed bond Answer broken so that each atom joined by the bond gets one of the two electrons in the bond benzoyl peroxide Answer example of a radical initiator (o-o bond = weak and can undergo homolysis upon heat or UV exposure to produce 2 benzoyl radicals) how much initiator is needed in polymerization and does any remain at the end of the reactions? Answer only a small amount of radical initiator is needed compared to the concentration of monomers present -some remains in final product but it does not affect the product two main things that control polymer properties Answer 1. the monomer used 2. the molecular weight of the final polymer chain what happens after the radical initiator has formed radicals? Answer radical can attack + homolyze C=C of monomer to create a reactive intermediate that starts polymerization which substituent does the radical add to in the monomer? Answer adds to the LEAST substituted carbon of the C=C bond because this carbon is easier to approach and less hindered to produce a more stable radical intermediate What happens during propagation of free-radical polymerization? Answer produces a new radical that can continue the polymerization chain reaction: Each attack of the radical with a new monomer unit extends the chain by one unit what is chain propagation the same as? Answer some step as initiation in that monomers add in head to tail fashion with substituents present on alternating carbons in the chain What 4 main factors determine the extent of the polymerization? 1. temperature 2. pressure 3. solvent used 4. monomer concentration speed of free radical chain growth Answer extremely rapid- can grow by thousands of monomers in less than a second Termination of free-radical polymerization Answer stops the chain growth, involves 2 radical species- pairing of 2 unpaired electrons and formation of new covalent bond 2 pathways of termination Answer 1. Radical Coupling 2. Radical Disproportionation Radical Coupling termination of free-radical polymerization where 2 radicals combine using the unpaired electrons on each to make a new covalent bond monomer arrangement in radical coupling head-to-head arrangement, substituents are attached to adjacent carbons radical disproportionation One radical abstracts a hydrogen atom from another radical species which forms a new covalent bond and makes and alkane- then an alkene is formed by the combination of unpaired electrons on adjacent carbons Radical Coupling AND radical disproportionation form what type of species from radical species? both form non-radical species from radical species which stops the growth of the polymer chain 3 steps in a Chain Reaction of free-radical polymerization 1. Initiation 2. Propagation 3. Termination Initiation of Free Radicals production of a radical species from a non-radical species using heat or UV light Propagation of Free Radicals reaction of a radical with a non-radical producing a new radical species and continuing the chain reaction what is chain transfer dependent on? Rates of the straight chain propagation steps versus the chain transfer steps -Rates are controlled by stability of the intermediate radicals that form as a product in each Termination of Free Radicals reaction of 2 radicals with each other producing a non-radical- no intermediate reactive = reaction stops chain transfer reaction type of propagation step where a radical in one polymer chain abstracts a hydrogen atom from a position in a different polymer chain which causes branching in a growing polymer chain Cation Chain-Growth Polymerization best for substrates that can form stable carbocation intermediates (typically unsubstituted substrates like bulky alkenes or alkenes with electron-donating substituents) How is cation addition polymerization initiated? By adding a strong acid to an alkene to form a carbocation intermediate cation addition polymerization propagation carbocation intermediate + new alkene monomer molecule adds one unit to the polymer chain each time cation addition polymerization termination terminates by the removal of a hydrogen atom from a carbon atom adjacent to the positively charged carbon to form an alkene (like in an elimination reaction) main catalysts used for anionic addition polymerization Grignard Reagents (R: -[MgBr]+) Alkyllithium (R:-Li+) Anionic addition polymerization a form of chain-growth polymerization or addition polymerization that involves the polymerization of monomers initiated with anions. The type of reaction has many manifestations, but traditionally vinyl monomers are used. Why use anionic addition polymerization useful for alkenes with electron-withdrawing substituents such as cyano groups, phenyls, esters anionic addition polymerization propagation chain grows by 1 anionic intermediate adding to the C=C bond of a monomer molecule. monomer anion adds in place of a Grignard Reagent or Alkyllithium reagent. each addition grows by one unit anionic addition polymerization termination accomplished by quenching reaction with a proton source such as water or alcohol what is formed when a monosubstituted alkene monomer is polymerized? a new chiral center is formed at every position where the substituent branches from the back bone of the chain Tacticity describes the location in the polymer chain of chiral centers rather than using R or S designation 3 main classes of polymer tacticity 1. Atactic 2. Isotactic 3.Syndiotactic atactic stereocenters have random configurations Isotactic all stereocenters have the same configuration syndiotactic Stereocenters alternate in configuration atactic configuration is labeled as Stereorandom isotactic and syndiotactic are labeled as Stereoregular How does having different tacticity with the same monomer effect the monomer? The same monomers with different tacticity will have different physical properties EX: atactic polypropylene (soft matrix adhesive) vs isotactic polypropylene (high-melting solid that can be molded or machined) 2 ways to control polymer stereochemistry 1. chain-end control 2. site control preferential formation of chain-end control -1st chiral center that forms will determine all subsequent stereochemistry in the polymer -an existing chiral center will force an incoming group to one side of the molecule Chain end control at an existing stereocenter and the end of the chain, the next monomer will be influenced by how the chiral center projects into space Site Control The specific shape of the reagent or catalyst that facilitates the reaction also determines the stereochemistry. Ziegler-Natta catalyst most famous site control to prod stereoregular polymers. uses various transition metal catalysts to control sites where monomers are added to the chain Ligands A molecule that binds specifically to a receptor site of another molecule. -coordinated to the metal ion that bind monomers prior to insertion into the growing chain -specifically utilized in Ziegler-Natta catalysts what 2 factors of ligands orient monomers into position shape and size hold monomers into position in ONE orientation what two types of polymers can Ziegler-Natta catalysts be used on? Isotactic and Syndiotactic (only stereoregular polymers) Homopolymer a polymer made up of one type of repeating unit. It is made from one monomer only. Copolymer polymers composed of more than one type of monomer -used to control properties of a polymer product (like flexibility or chemical resistance) Random (Statistical) Copolymer monomeric units distributed randomly and unevenly in the chain Alternating Copolymer monomeric units distributed regularly + alternating with nearly equimolar amounts in each chain Block Copolymer long sequence/ blocks of one monomer is joined to a block of the second monomer Graft Copolymer side chains of a given monomer are attached to main chains of a second monomer biggest causative agent of the exact sequence in copolymer chains: relative reactivity of the monomers present situation creates what copolymer? A reacts rapidly with B but slow with self B reacts rapidly with A but slow with self alternating sequence (ABABABABABA) two things that determine the reactivity of a monomer 1. number of substituents present 2. type of substituents present situation creates what copolymer? A and B are equally reactive towards each other and self random sequence (ABBAAAAABABBBAABBBBBBBAABABBB) situation creates what copolymer? One monomer in in copolymer is more reactive than other to all species mixture of two different homopolymers situation creates what copolymer? polymerization of monomer A is iniated, then B is added, then A is added, etc -particularly useful for anionic polymerization bc the living end (anion) stays active until the reaction is quenched. Block sequence situation creates what copolymer? first polymerize a monomer with additional functionality (a second double bond) in its structure -makes a polymer with multiple bonds -homopolymer is formed -monomer B added with a radical initiator to graft section of B onto reactive sites of A. Graft sequence polymer properties are strongly affected by: 1. molecular weight (and distribution) 2. amount of branching (of the chain architecture) how do long branches affect crystallinity? undergo side-chain crystallization (able to form rows of crystals on their own) how do short branches affect crystallinity? Reduce crystallinity (interfere with the formation of crystals) Amorphous polymers polymer chains arranged in random manner- not regularly aligned as in a crystal important example of an amorphous polymer polystyrene (monomer styrene ((Vinyl Benzene))) thermoplastic softens upon heating and hardens upon cooling (property of polystyrene) what is produced by adding a low boiling inert solvent like pentane to the polymerization reaction of polystyrene where the pentane boils off into gas and the volatilization causes bubbles that expand the polymer into a foam. Styrofoam What allows amorphous polymers to be made more rigid/ crystalline (and thus less amorphous) Cross-Linking Cross-linking definition small amounts of polyfunctional monomers are added to form links (covalent bonds between growing chains) these links tether the growing chains together in a less random, more crystalline order characteristics of cross-linked polystyrene more rigid, less soluble in organic solvents than native what are the main properties that characterization techniques of polymers seek to discover? molecular mass, molecular structure, morphology, thermal properties, mechanical properties molecular mass of polymers differs from typical molecules d/t polymerization reaction producing a distribution of molecular weights and shapes molecular mass of polymers = average molecular weight and polydispersity Polydisperity (PD) how heterogenous the range of particle size is Spectroscopy: UV-visible, infrared, Ramen, Nuclear magnetic resonance, electron spin resonance, xray diffraction, mass spectrometry techniques used to characterize polymers by identifying common function groups + other structure features (also used to determine molecular structure of unknown molecules) an atom has gained or lost electrons ion a characteristic of atom that varies regularly across the periodic table periodic property a compound held together by a shared pair of valence electrons covalent compound a compound formed by ions ionic compound the electrons that exist farthest from the atom's nucleus and generally have the highest energy level number valence electrons most atoms strive to attain eight valence electrons octet rule an indicator of an atom's size atomic radius the amount of energy needed in order to take an electron away from an atom ionization potential a measure of how strongly an atom attracts extra electros to itself a electronegativity the process by which an atom turns into an ion by gaining or losing electrons ionization Show Less
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